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Ierofanga [76]
3 years ago
5

What percentage is 122 out of 222?

Engineering
2 answers:
Evgesh-ka [11]3 years ago
6 0

Answer:

About 54-55% It depends on if you need to round.

Explanation:

den301095 [7]3 years ago
4 0

Answer:

Divide the first number by the second.

Explanation:

~55%

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What are the constraints of the problem for thermoforming
Inga [223]

Answer:

here are four options so you can choose the ones of your choice.

Explanation:

1. warpage

2 Dimensional Inconsistencies

3 Part Thickness Inconsistencies

4 Lack of Detail in Part Geometry and Aesthetics

please rate brainliest if helps and follow

6 0
2 years ago
Plastic parts produced by an injection-molding operation are checked for conformance to specifications. Each tool contains 11 ca
Wittaler [7]

Answer:

a) 0.27 %                                  b) 0.27%

Explanation:

a) The inspector can choose 1 part from 11 parts in  11C1 ways. These are total number of mutually exclusive events.

Now three cavities are effected by temperature Malfunction that results in the parts that do not conform to specifications. To obtain exactly 1 non conforming part the inspector have to choose from one of the three cavities that are effected by temperature. This can be done in 3C1 ways.

Probability that inspector finds out exactly 1 non conforming part is,

Probability = \frac{3C1}{11C1}  

         Probability  =    \frac{\frac{3!}{1!(3-1)!} }{\frac{11!}{1!(11-1)!} }     = 3 / 11

                            =  0.27 %

b)  As the inspector is choosing only 1 part for inspection so the probability to find exactly 1 non conforming part is same as the probability to find at least 1 non conforming part.

    So the probability is 0.27 %.

8 0
4 years ago
What type of cable communicates binary data by changing the voltage between two ranges?
Mila [183]
The sending device communicates binary data across these copper wires by changing the voltage between two ranges. The system at the receiving end is able to interpret these voltage changes as binary ones and zeros which can then be translated into different forms of data.
6 0
4 years ago
A rigid tank holds 22 kg of 127 °C water. If 9 kg of that is liquid water what is the pressure in the tank and volume of the tan
ipn [44]

Answer:

The pressure and volume of the tank are 246.878 Kpa and 9.449 m³ respectively.

Explanation:

Volume is constant as the tank is rigid. Take the saturation condition of water from the steam table for pressure at 127°C.  

Given:  

Total mass of water is 22 kg.  

Mass of liquid water is 9 kg.  

Temperature of water is 127°C.  

From steam table at 127°C:  

The pressure in the tank is 246.878 Kpa.  

Specific volume of saturated water is 0.00106683 m³/kg.  

Specific volume of saturated steam is 0.72721 m³/kg.  

Calculation:  

Step1  

From steam table at 127°C:  

The pressure in the tank is 246.878 Kpa.  

Step2  

Dryness fraction is calculated as follows:  

x=\frac{m_{v}}{m_{t}}

Here, dyness fraction is x, mass of vapor is m_{v}and total mass is m_{t}.  

Substitute the values in the above equation as follows:  

x=\frac{m_{v}}{m_{t}}

x=\frac{22-9}{22}

x = 0.59  

Step3  

Specific volume of tank is calculated as follows:  

v=v_{f}+x(v_{g}-v_{f})

v=0.00106683+0.59(0.72721-0.00106683)

v=0.00106683+0.42842447

v=0.4295 m³/kg.  

Step4  

Volume is calculated as follows:  

V=v\times m_{t}

V=0.4295 \times22

V=9.449 m³.  

Thus, the pressure and volume of the tank are 246.878 Kpa and 9.449 m³ respectively.

8 0
4 years ago
If necessary, open the Cleanup Animator and choose the Shuffle Left algorithm from the Select Algorithm drop-down list. Click Ru
jek_recluse [69]

Answer:

A = 42 32 0 0 0 77 23 71 is the list of numbers taken here as the question is incomplete.

L marker moves to the right trying to detect 0s. Each time it detects a 0, the R marker moves to the right, shuffling the data items to the left.

Get the array, A and its size, n

L = 1

R = 2

Repeat the following steps until left > legit

if AL ≠ 0

L ++

R ++

else

legit --

Repeat the following steps until right > n

Copy AR to AR

R ++

R = L + 1

stop

Explanation: The arrangement of data is as follows:

A = 42 32 0 0 0 77 23 71

N = 8; L= 1; R = 2

Iteration 1: 42 ≠ 0 => L = 2; R = 3

A = 42 32 0 0 0 77 23 71

Iteration 2: 32 ≠ 0 => L = 3; R = 4

A = 42 32 0 0 0 77 23 71

Iteration 3: 0 = 0 => N = 7

Copy the remaining elements one position to its left

A = 42 32 0 0 77 23 71

Iteration 4: 0 = 0 => N = 6

Copy the remaining elements one position to its left

A = 42 32 0 77 23 71

Iteration 5: 0 = 0 => N = 5

Copy the remaining elements one position to its left

A = 42 32 77 23 71

Iteration 6: 77 ≠ 0 => L = 4; R = 5

A = 42 32 77 23 71

Iteration 7: 23 ≠ 0 => L= 5; R = 6

A = 42 32 77 23 71

Iteration 8: 71 ≠ 0 => L= 6; R = 7

A = 42 32 77 23 71

L > N ---- stop

final arrangement of the data when the algorithm terminates

42 32 77 23 71

3 0
4 years ago
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