Answer:
C_h = 0.166 nF
C_L = 0.153 nF
Explanation:
Given:
- Ideal frequency f_o = 500 KHz
- Bandwidth of frequency BW = 40 KHz
- The resistance identical to both low and high pass filter = 2 Kohms
Find:
Design a passive band-pass filter to do this by cascading a low and high pass filter.
Solution:
- First determine the cut-off frequencies f_c for each filter:
f_c,L for High pass filter:
f_c,L = f_o - BW/2 = 500 - 40/2
f_c,L = 480 KHz
f_c,h for Low pass filter:
f_c,h = f_o + BW/2 = 500 + 40/2
f_c,h = 520 KHz
- Now use the design formula for R-C circuit for each filter:
General design formula:
f_c = 1 /2*pi*R*C_i
C,h for High pass filter:
C_h = 1 /2*pi*R*f_c,L
C_h = 1 /2*pi*2000*480,000
C_h = 0.166 nF
C,L for Low pass filter:
C_L = 1 /2*pi*R*f_c,h
C_L = 1 /2*pi*2000*520,000
C_L = 0.153 nF
Answer:
There are three basic Boolean operations: JOIN (Union), CUT (Difference), and INTERSECT. ... The CUT operation subtracts the volume of one solid object from the other solid object. The INTERSECT operation keeps only the volume common to both solid objects.
Answer:
Yes it is possible
Explanation:
<u>Procedures to be taken:</u>
<u>Step 1:</u>
I will deform the specimen, that is, I will subject the specimen to plastic deformation at room temperature.
<u>Step 2:</u>
Also, I will anneal the deformed specimen at a high temperature.
<u>Step 3:</u>
Then, recrystallize the annealed specimen
<u>Step 4:</u>
Finally, I will facilitate the grain growth until the average grain diameter becomes 0.02mm.
Answer:
Using linkedlist on C++, we have the program below.
Explanation:
#include<iostream>
#include<cstdlib>
using namespace std;
//structure of linked list
struct linkedList
{
int data;
struct linkedList *next;
};
//print linked list
void printList(struct linkedList *head)
{
linkedList *t=head;
while(t!=NULL)
{
cout<<t->data;
if(t->next!=NULL)
cout<<" -> ";
t=t->next;
}
}
//insert newnode at head of linked List
struct linkedList* insert(struct linkedList *head,int data)
{
linkedList *newnode=new linkedList;
newnode->data=data;
newnode->next=NULL;
if(head==NULL)
head=newnode;
else
{
struct linkedList *temp=head;
while(temp->next!=NULL)
temp=temp->next;
temp->next=newnode;
}
return head;
}
void multiplyOddPosition(struct linkedList *head)
{
struct linkedList *temp=head;
while(temp!=NULL)
{
temp->data = temp->data*10; //multiply values at odd position by 10
temp = temp->next;
//skip odd position values
if(temp!= NULL)
temp = temp->next;
}
}
int main()
{
int n,data;
linkedList *head=NULL;
// create linked list
head=insert(head,20);
head=insert(head,5);
head=insert(head,11);
head=insert(head,17);
head=insert(head,23);
head=insert(head,12);
head=insert(head,4);
head=insert(head,21);
cout<<"\nLinked List : ";
printList(head); //print list
multiplyOddPosition(head);
cout<<"\nLinked List After Multiply by 10 at odd position : ";
printList(head); //print list
return 0;
}
Answer:
B probably
Explanation:
Because the prompt doesn't specify what sort of violation it could be anything maybe when they release the metals during the day and so on.
