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Korvikt [17]
3 years ago
14

A marble statue stands on a square pedestal whose side lengths are 2.30 m. Together the statue and the pedestal weigh 3450 N. Wh

at is the pressure the statue exerts on the floor in Pa
Chemistry
2 answers:
fenix001 [56]3 years ago
8 0

Answer:

Pressure = 652 Pa (Approx)

Explanation:

Given:

Total weigh = 3,450 N

Side length = 2.3 m

Find:

Pressure

Computation:

Area of statute = side x side

Area of statute = 2.3 x 2.3

Area of statute = 5.29 m²

Pressure = Weight / Area

Pressure = 3,450 / 5.29

Pressure = 652 Pa (Approx)

alexira [117]3 years ago
4 0

Answer:652

Explanation: it’s the answer

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Nitrogen dioxide reacts with carbon monoxide to produce nitrogen monoxide and carbon dioxide. NO2(g) + CO(g) ⟶ NO(g) + CO2(g) A
Naya [18.7K]

<u>Answer:</u> The rate law for the reaction is \text{Rate}=k[NO_3][CO]

<u>Explanation:</u>

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

In a mechanism of the reaction, the slow step in the mechanism determines the rate of the reaction.

For the given chemical reaction:

NO_2(g)+CO(g)\rightarrow NO(g)+CO_2(g)

The intermediate reaction of the mechanism follows:

Step 1:  2NO_2(g)\rightleftharpoons NO_3(g)+NO(g);\text{ (fast)}

Step 2:  NO_3(g)+CO(g)\rightarrow NO_2(g)+CO_2(g);\text{(slow)}

As, step 2 is the slow step. It is the rate determining step

Rate law for the reaction follows:

\text{Rate}=k[NO_3][CO]

Hence, the rate law for the reaction is written above.

5 0
4 years ago
A student mixes in a test tube 3.00mL of 0.050M CuSO4with 7.00mL of 0.20M NH3/NH41 . The solution becomes a deep blue color. Ass
valkas [14]

Answer:

\large \boxed{\text{0.0035 mol/L}}

Explanation:

We are given the volumes and concentrations of two reactants, so this is a limiting reactant problem.

We know that we will need moles, so, lets assemble all the data in one place.

                   Cu²⁺ + 4NH₃ ⟶ Cu(NH₃)₄²⁺

    V/mL:   3.00      7.00

c/mol·L⁻¹:  0.050   0.20

1. Identify the limiting reactant

(a) Calculate the moles of each reactant  

\text{Moles of Cu}^{2+}= \text{3.00 mL solution} \times \dfrac{\text{0.050 mmol Cu}^{2+}}{\text{1 mL solution}} = \text{0.150 mmol Cu}^{2+}\\\\\text{Moles of NH}_{3} = \text{7.00 mL solution} \times \dfrac{\text{0.20 mmol NH}_{3}}{\text{1 mL solution}} = \text{0.140 mmol NH}_{3}

(b) Calculate the moles of Cu(NH₃)₄²⁺ that can be formed from each reactant

(i) From Cu²⁺

\text{Moles of Cu(NH$_{3}$)$_{4}$$^{2+}$} = \text{0.150 mmol Cu}^{2+} \times \dfrac{\text{1 mmol Cu(NH$_{3}$)$_{4}$$^{2+}$}}{\text{1 mmol Cu}^{2+}}\\\\= \text{0.150 mmol Cu(NH$_{3}$)$_{4}$$^{2+}$}

(ii) From NH₃

\text{Moles of Cu(NH$_{3}$)$_{4}$$^{2+}$} = \text{0.140 mmol NH}_{3} \times \dfrac{\text{1 mmol Cu(NH$_{3}$)$_{4}$$^{2+}$}}{\text{4 mmol NH}_{3}}\\\\= \text{0.0350 mmol Cu(NH$_{3}$)$_{4}$$^{2+}$}

NH₃ is the limiting reactant, because it forms fewer moles of the complex ion.

(c) Concentration of the complex ion

\text{The reaction forms 0.0350 mmol Cu(NH$_{3}$)$_{4}$$^{2+}$ in a total volume of 10.00 mL.}\\c = \dfrac{\text{moles}}{\text{litres}} = \dfrac{\text{0.0350 mmol}}{\text{10.00 mL}} = \textbf{0.0035 mol/L}\\\\\text{The concentration of the complex ion is $\large \boxed{\textbf{0.0035 mol/L}}$}

7 0
3 years ago
How does the arrangement of the particles in a gas compare to that of a solid
blondinia [14]
The particles of the gases are apart from each other and they are movingoing freely, However, in the solid the particles are very close to each other and there is no spaces between them,
7 0
3 years ago
What is The maximum amount of a substance that can be dissolved by another substance
Oksanka [162]

Solubility varies vastly. It depends on the solute, solvent, temperature, and pressure.

6 0
3 years ago
94.9 grams of Br is equivalent to how many moles of Br?
Mashutka [201]

Answer:

The answer is 79.904.

Explanation:

We assume you are converting between grams Br and mole.

You can view more details on each measurement unit:

molecular weight of Br or mol

The SI base unit for amount of substance is the mole.

1 grams Br is equal to 0.012515018021626 mole.

Note that rounding errors may occur, so always check the results.

Use this page to learn how to convert between grams Br and mole.

Type in your own numbers in the form to convert the units!

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3 years ago
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