<span>The answer is H2CO itcontains both sigma and pi bonds.</span>
SO2<span> molecule </span>have a dipole moment<span> and a </span>CO2<span> molecule doesn't ... </span>Dipole moment<span> of </span>CO2<span> molecule </span>is zero<span>,becoz it is linear molecule,whereas </span>SO2<span> is angular</span>
Answer:
Before the equivalence point, conductivity is decreasing. After the equivalence point, conductivity is increasing
Explanation:
In solution H2SO3 produce H+ ions and SO3²⁻ ions. In the same way, NaOH produce Na⁺ and OH⁻ ions. The conductivity of a solution is directly proportional to the concentration of ions in a solution. During titration, you are adding more NaOH (That is, more Na⁺ and OH⁻ ions). But each moles of OH⁻ reacts with H⁺ ion producing H₂O. That means the moles of Na⁺ that you are adding = Moles of H⁺ are been consumed. The concentration of ions remains approximately constant. But, H⁺ ion conducts better than Na⁺ ion. That means before the equivalence point, conductivity is decreasing. But after the equivalence point you will add OH- ions in excess increasing ion concentration increasing the conductivity:
After equivalence point, conductivity is increasing.
Rubidium would exhibit the greatest shielding [ effect. ]
Answer and Explanation:
It is not necessary to know the amount of salt in the aqua, because we know that the presence of salt in the water will increase its density.
In this case, salt increases the mass of the water, without increasing the volume of water. as the egg will not change in volume or water, we know that the density of the egg will be constant, while the change in the mass of the water with the addition of salt, will change the density of the water which will increase progressively until it becomes denser than the egg and, consequently, it will not let the egg sink.
