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PIT_PIT [208]
3 years ago
5

Which molecule is pentanoic acid? ОА. Н 1 НЕС-ОН ОВ. Н ОН ор.н.н

Chemistry
1 answer:
kicyunya [14]3 years ago
4 0

Answer:

PubChem CID 7991

Structure Find Similar Structures

Chemical Safety Laboratory Chemical Safety Summary (LCSS) Datasheet

Molecular Formula C5H10O2 or CH3(CH2)3COOH

Synonyms Valeric acid PENTANOIC ACID n-Valeric acid 109-52-4 n-Pentanoic acid More.

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List planets of rocks
irina [24]

Answer:

in our solar system, the rocky planets are Mercury, Venus, Earth, and Mars

hope this helps :)

Explanation:

6 0
3 years ago
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What is the main way that heat passes through a brick in the wall of a building?
Luden [163]

its conduction

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Let me know if ther is an error in my answer

8 0
3 years ago
When 5.58g H2 react by the following balanced equation, 32.8g H2O are formed. What is the percent yield of the reaction? 2H2(g)+
8090 [49]

Answer:

D) 65.7%

Explanation:

Based on the reaction:

2H2(g)+O2(g)⟶2H2O(l)

<em>2 moles of hydrogen produce 2 moles of water assuming an excess of oxygen.</em>

<em />

To find percent yield of the reaction we need to find theoretical yield (The yield assuming all hydrogen reacts producing water). With theoretical yield and actual yield (32.8g H₂O) we can determine percent yield as 100 times the ratio between actual yield and theoretical yield.

<em>Theoretical yield:</em>

Moles of 5.58g H₂:

5.58g H₂ ₓ (1 mol / 2.016g) = 2.768 moles H₂

As 2 moles of H₂ produce 2 moles of H₂O, if all hydrogen reacts will produce 2.768 moles H₂O. In grams:

2.768 moles H₂O ₓ (18.015g / mol) =

49.86g H₂O is theoretical yield

<em>Percent yield:</em>

Percent yield = Actual yield / Theoretical yield ₓ 100

32.8g H₂O / 49.86g ₓ 100 =

65.7% is percent yield of the reaction

<h3>D) 65.7% </h3>

4 0
3 years ago
I have four neutrons and I'm metallic. Who am<br> I?
Mekhanik [1.2K]
Beryllium has four neutrons
8 0
3 years ago
Read 2 more answers
No spam or links! Thanks!
Monica [59]

Answer:

364 K or 91°C

Explanation:

Applying,

V₁/T₁ = V₂/T₂................ Equation 1

Where V₁ = Initial Volume, V₂ = Final volume, T₁ = initial Temperature, T₂ = final Temperature.

make T₂ the subject of the equation,

T₂ = V₂T₁/V₁................. Equation 2

From the question,

Given: V₁ = 375 mL, V₂ = 500 mL, T₁ = 0.0°C = (273+0) K = 273 K

Substitute these values into equation 2

T₂ = (500×273)/375

T₂ = 364 K

T₂ = (364-273) °C = 91 °C

5 0
3 years ago
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