first of all there is only two types of selective breeding and they are hybridization and inbreeding.
Answer:
The empirical formula would be N₂Os * Page 2 Calculate the empirical formulaof a compound that is 94.1% oxygen, 5.9% hydrogen.
HM, I think the answer would be D. This is just a guess, so please use it if ou want to answer D it's ok :D
Answer:
0.20 mol's
Explanation:
1.675 L = 1.675 dm^3
moles = V/(conc):
moles = 1.675/(8.5)
moles = 0.1970... --> 0.20
Answer:
Molar concentration of CO₂ in equilibrium is 0.17996M
Explanation:
Based on the reaction:
NiO(s) + CO(g) ⇆ Ni(s) + CO₂(g)
kc is defined as:
kc = [CO₂] / [CO] = 4.0x10³ <em>(1)</em>
As initial concentration of CO is 0.18M, the concentrations in equilibrium are:
[CO] = 0.18000M - x
[CO₂] = x
Replacing in (1):
4.0x10³ = x / (0.18000-x)
720 - 4000x = x
720 = 4001x
x = 0.17996
Thus, concentrations in equilibrium are:
[CO] = 0.18000M - 0.17996 = 4.0x10⁻⁵
[CO₂] = x = <em>0.17996M</em>
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Thus, <em>molar concentration of CO₂ in equilibrium is 0.17996M</em>
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I hope it helps!
