Answer:
0.00370 g
Explanation:
From the given information:
To determine the amount of acid remaining using the formula:
where;
v_1 = volume of organic solvent = 20-mL
n = numbers of extractions = 4
v_2 = actual volume of water = 100-mL
k_d = distribution coefficient = 10
∴




Thus, the final amount of acid left in the water = 0.012345 * 0.30
= 0.00370 g
Answer:
active because he built up antibodies due to exposure to the flu
Explanation:
Answer:
The different structures are shown in the attachment.
I and II - structural isomers
I and III - Structural isomers
I and IV - structural isomers
II and III - structural isomers
II and IV - structural isomers
III and IV - stereoisomers
Explanation:
The knowledge of Isomerism is tested here; there are two types of isomerism ; structural and stereoisomerism.
- Structural Isomers have similar molecular and different double bond positioning, these occurs mostly in ALKENE FAMILY.
- Stereo-isomers have the same molecular formular and similar patterns but differ in their spatial arrangement. trans and cis are typical examples of stereo-isomers.
From the question; Relationship between I and II is that they are structural isomers since they have the same molecular formula, but different bond atom arrangement and infact they are the same compound.
- Relationship between I and III is that they are structural isomers with similar molecular formular but differ in the double bond position.
- Relationship between I and IV is that they are structural isomers with similar molecular formula but different double bond arrangement.
- Relationship between II and III is that they are structural isomers with similar molecular formular but different double bond position
- Relationship between II and IV is that they are also structural isomers with the same molecular formular but different double bond position.
- Relationship between III and IV is that they are stereo-isomers with same molecular formula but different spatial arrangement, hence cis and trans.
The mass of Copper deposited at the cathode : 0.296 g
<h3>Further explanation</h3>
Given
time = t = 10 min=600 s
current = i = 1.5 A
F = 96500 C
charge Cu=+2
Required
The mass of Copper
Solution
Faraday's Law

e = Ar/valence(valence Cu=2, Ar=63.5 g/mol)
Input the value :

The answer is (3) pH 3 to pH 1. The pH is related to the concentration of H3O+ with the relationship: pH = -lg c(H+). So when concentration of H3O+ increase, the pH will decrease. And decrease 2 when when increase hundredfold. Because 100=10^2.