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Novay_Z [31]
3 years ago
9

When shopping for major appliances, people should look for high energy-rating numbers because those items _____.

Chemistry
2 answers:
madam [21]3 years ago
6 0
The answer would be :Use less energy
Dmitry_Shevchenko [17]3 years ago
3 0

Answer:

Use less energy.

Explanation:

Hello,

High energy consumption implies higher costs during the usage of a product, nevertheless, by avoiding this factor, money could be saved in addition of the environmental damage that is prevented in the light of the lower energy use.

Best regards.

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Which statement is true about how scientists draw conclusions from data?
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I believe the answer is D.
Scientists are biased, and want to prove their specific hypothesis is right.
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3 years ago
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1.0 x 10^2 m what is the frequency of the waves
MAVERICK [17]

Answer:

f = 3 × 10⁶ Hz

Explanation:

Given data:

Wavelength of wave = 1.0 ×10² m

Frequency = ?

Solution:

Formula:

Speed of light = wavelength× frequency

Frequency = speed of light / wavelength

speed of light = 3× 10⁸ m/s

f = 3× 10⁸ m/s / 1.0 ×10² m

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f = 3 × 10⁶ Hz

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Please help me with my "Math Skills" thanks
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What types of orbital overlap occur in cumulene? check all that apply. check all that apply. p/p overlap sp/sp2 overlap s/sp ove
egoroff_w [7]
Cumulene is an alkene hydrocarbon that has two or three double bonds. It is also known as allene. The simplest cumulene is butatriene. It is a rigid hydrocarbon due to the presence of double bonds.

Answer: The orbital that overlap are p/p overlap, s/sp2 overlap, sp/sp2 overlap and sp/sp orbital.
8 0
3 years ago
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what will the new volume of a 22.4L same of a gas at STP if the pressure remains constant and the temperature is cut in half? A.
In-s [12.5K]

Answer:

\boxed{\text{C. 11.2 L}}

Explanation:

The pressure is constant, so we can use Charles' Law to calculate the volume.

\dfrac{V_{1}}{T_{1}} = \dfrac{V_{2}}{T_{2}}

Data:

V₁ = 22.4 L; T₁ = 273.15 K

V₂ = ?;         T₂ = 136.58 K

Calculations:

\dfrac{ 22.4}{273.15} = \dfrac{ V_{2}}{136.58}\\\\0.082 00 = \dfrac{ V_{2}}{136.58}\\\\V_{2} =0.082 00 \times 136.58 = \boxed{\textbf{11.2 L}}

5 0
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