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2 years ago

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What is the answer of 603 x 42 , this question is multiply , it’s of my brother who is just in g-4 …… pls help if you know but t

each by process

1 answer:

satela [25.4K]2 years ago

4 0

Answer:

<h2>25326</h2>

Step-by-step explanation:

please refer to the picture above

$\tt{ \green{P} \orange{s} \red{y} \blue{x} \pink{c} \purple{h} \green{i} e}$

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The blades of a windmill turn on an axis that is 35 feet above the ground. The blades are 10 feet long and complete two rotation

Alona [7]

Answer:

h = 10sin(π15t)+35

Step-by-step explanation:

The height of the blade as a function f time can be written in the following way:

h = Asin(xt) + B, where:

B represets the initial height of the blade above the ground.

A represents the amplitud of length of the blade.

x represents the period.

The initial height is 35 ft, therefore, B = 35ft.

The amplotud of lenth of the blade is 10ft, therefore A = 10.

The period is two rotations every minute, therefore the period should be 60/4 = 15. Then x = 15π

Finally the equation that can be used to model h is:

h = 10sin(π15t)+35

5 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=5x-4%2B2%28x-4%29%3D16" id="TexFormula1" title="5x-4+2(x-4)=16" alt="5x-4+2(x-4)=16" align="ab

mariarad [96]

Answer:

$\boxed{x = 4}$

Step-by-step explanation:

=> 5x-4+2(x-4) = 16

Expanding the brackets

=> 5x-4+2x-8 = 16

Combining like terms

=> 5x+2x-4-8 = 16

=> 7x - 12 = 16

Adding 12 to both sides

=> 7x = 16+12

=> 7x = 28

Dividing both sides by 7

=> x = 4

3 0

2 years ago

Read 2 more answers

Find two power series solutions of the given differential equation about the ordinary point x = 0. compare the series solutions

monitta

I don't know what method is referred to in "section 4.3", but I'll suppose it's reduction of order and use that to find the exact solution. Take $z=y'$ , so that $z'=y''$ and we're left with the ODE linear in $z$ :

$y''-y'=0\implies z'-z=0\implies z=C_1e^x\implies y=C_1e^x+C_2$

Now suppose $y$ has a power series expansion

$y=\displaystyle\sum_{n\ge0}a_nx^n$
$\implies y'=\displaystyle\sum_{n\ge1}na_nx^{n-1}$
$\implies y''=\displaystyle\sum_{n\ge2}n(n-1)a_nx^{n-2}$

Then the ODE can be written as

$\displaystyle\sum_{n\ge2}n(n-1)a_nx^{n-2}-\sum_{n\ge1}na_nx^{n-1}=0$

$\displaystyle\sum_{n\ge2}n(n-1)a_nx^{n-2}-\sum_{n\ge2}(n-1)a_{n-1}x^{n-2}=0$

$\displaystyle\sum_{n\ge2}\bigg[n(n-1)a_n-(n-1)a_{n-1}\bigg]x^{n-2}=0$

All the coefficients of the series vanish, and setting $x=0$ in the power series forms for $y$ and $y'$ tell us that $y(0)=a_0$ and $y'(0)=a_1$ , so we get the recurrence

$\begin{cases}a_0=a_0\\\\a_1=a_1\\\\a_n=\dfrac{a_{n-1}}n&\text{for }n\ge2\end{cases}$

We can solve explicitly for $a_n$ quite easily:

$a_n=\dfrac{a_{n-1}}n\implies a_{n-1}=\dfrac{a_{n-2}}{n-1}\implies a_n=\dfrac{a_{n-2}}{n(n-1)}$

and so on. Continuing in this way we end up with

$a_n=\dfrac{a_1}{n!}$

so that the solution to the ODE is

$y(x)=\displaystyle\sum_{n\ge0}\dfrac{a_1}{n!}x^n=a_1+a_1x+\dfrac{a_1}2x^2+\cdots=a_1e^x$

We also require the solution to satisfy $y(0)=a_0$ , which we can do easily by adding and subtracting a constant as needed:

$y(x)=a_0-a_1+a_1+\displaystyle\sum_{n\ge1}\dfrac{a_1}{n!}x^n=\underbrace{a_0-a_1}_{C_2}+\underbrace{a_1}_{C_1}\displaystyle\sum_{n\ge0}\frac{x^n}{n!}$

4 0

3 years ago

PLEASE HELP!!!!!!!!!!!!!

Marianna [84]

Answer:

d

Step-by-step explanation:

formula for area of a triangle is base * width * 1/2

7 0

3 years ago

Two joggers run 8 miles north and 5 miles west . what is the shortest distance, to the nearest tenth of a mile, they must travel

kobusy [5.1K]

Answer:9.4 miles

Hope this helps

6 0

2 years ago