Answer:
Carbohydrates, particularly glycoproteins act as ligands for cell surface receptors.
Explanation:
Glycoproteins
- Glyproteins are conjugate molecules comprising of carbohydrates conjugated with proteins.
- Glycoproteins play a vital role in cell-cell recognition, pathogen recognition and and cell adhesion.
- Glycoproteins on the surface of pathogens act as prominent antigens for the immune system.
Glycoproteins in Fertilization:
Several glycoproteins are attached to the surface of the zona pellucida, the envelope of the oocyte. In humans, these have been termed as ZP1-4.
Glycoprotein-sperm interaction is one of the most crucial steps in fertilization. This receptor-ligand interaction ensures the entry of the sperm into the zona pellucida, the extracellular coat, covered in glycoproteins that surrounds the oocyte or egg.
Carbohydrate binding proteins present on the surface of the sperm recognize the glycoproteins on the zona pellucida (ZP). This enables them to adhere to the surface of the ZP and also to gain access to the oocyte.
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The answer is Alexander hamilton
Answer:
The light-dependent reactions use light energy to make two molecules needed for the next stage of photosynthesis: the energy storage molecule ATP and the reduced electron carrier NADPH. In plants, the light reactions take place in the thylakoid membranes of organelles called chloroplasts.
Explanation:
Answer:
64
Explanation:
Nitrogen combines directly with oxygen at very high temperatures to form nitrogen(ii) oxide. This is the reaction that occurs during lightning flashes. Atmospheric nitrogen and oxygen combines during the high temperatures obtained in lightning flashes to form nitrogen (ii) oxide.
Equation of the reaction is given below:
N(g) + O(g) ---> 2NO(g)
From the equation of the reaction, 1 mole of nitrogen gas combines with one mole of oxygen gas to produce 2 moles of nitrogen (ii) oxide.
Therefore, 2 moles of oxygen gas will react with 2 moles of nitrogen gas
Mass of oxygen gas that is 2 moles of the gas is obtained from the formula; mass = number of moles * molar mass
Molar mass of oxygen gas = 32.0 g/mol
Mass of 2 moles of oxygen gas = 2 * 32.0 = 56 g
Therefore, the mass of oxygen required in grams is 64