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stiv31 [10]
3 years ago
11

Which of the following statements is not true regarding atmospheric pressure?

Physics
1 answer:
Sergio [31]3 years ago
6 0
<span>The correct answer is option B. i.e.When atmospheric pressure is higher than the absolute pressure of a gas in a container, a partial vacuum exists in the container. This is the incorrect statement about atmospheric pressure and the absolute pressure.</span>
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In a parallel circuit with a 4 ohm and a 2 ohm resistor and a 12 volt source, what is the potential difference across the 4 ohm
sladkih [1.3K]

Answer:

12volts

Explanation:

The potential difference between 4ohm resistor is 12volts because equal voltage is dropped in both resistor.

5 0
4 years ago
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Daniel earned $8.00 per hour at his job. Daniel works 35 hours week. He received a 5% pay increase. How much more money will Dan
polet [3.4K]
Daniel will earn $2.20 more a week because his pay increase will increase his pay from $8 to $8.40
7 0
3 years ago
A block is hung by a string from the inside roof of a van. when the can goes straight ahead at a speed of 28 m/s, the block hang
Elis [28]

Answer:

θ =28.07⁰

Explanation:

when van moves around an unbanked curve, horizontal component of normal force is equal to centripetal force

F_{c}= F_{n} sin\theta

F_{n}sin\theta= \frac{mv^{2} }{r}---(1)

There is no motion in vertical direction, so vertical component of normal force is balanced with weight of block i.e.

F_{n}cos\theta= mg----(2)

divide (1) and (2)

\frac{F_{n}sin\theta}{F_{n}cos\theta} = \frac{\frac{mv^{2} }{r} }{mg}

tan \theta=\frac{v^{2} }{rg}

\theta=tan^{-1} \frac{v^{2} }{rg}

v = 28 m/s

r = 150 m

g = 9.8m/s^{2}

θ = 28.07⁰

5 0
3 years ago
Need help!!! A charge of 8.5 × 10–6 C is in an electric field that has a strength of 3.2 × 105 N/C. What is the electric force a
ddd [48]
B is the right answer. Multiply numbers you get the answer
3 0
3 years ago
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In the laboratory, a ball is dropped onto a force-sensing platform several times, each time hitting a different surface (foam, f
NeX [460]

Answer:

Graphing the momentum against the change in moment yields a linear relationship.

Explanation:

This is an impulse experiment,

          I = ∫ F .dt

where the force and time of the collision are measured, therefore if we assume an average force the integral reduces to

           I = F t

Furthermore, the momentum is equal to the change in moment of the ball, this change in moment can be found using the energy relations measuring the height of the ball and calculating its speed, in the two intervals for the descent and for the exit, possibly the heights are different so the moment change is different from zero.

Starting point. Higher

          Em₀ = U = mgh

Lower end point, just before hitting the scale

          Em_{f} = K = ½ m v²

in the path in the air there is no friction

          Em₀ = Em_{f}

          m g h = ½ m v²

          v = \sqrt{2gh}

this height is different for the descent and ascent of the ball, so we have two moments

         Δp = p_{f} - p₀

         Δp = m (v_{f} -v₀)

         

therefore we have the relationship

         

         I = Δp

Graphing the momentum against the change in moment yields a linear relationship.

5 0
3 years ago
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