Answer : The concentration of copper(II) fluoride in the solution is, 
Explanation : Given,
Moles of copper(II) fluoride = 0.032 μ
mol = 
conversion used : 
Volume of solution = 500 mL
Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.
Formula used :
Now put all the given values in this formula, we get:
Therefore, the concentration of copper(II) fluoride in the solution is,
Oxygen is the correct answer hope this helps
Answer
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shape:circle
texture: bumpy rough on side
color:brown
size: bigger than a quarter
Explanation:
I cant see it so just describe the color shape size texture
Answer:
V₂ = 21.3 dm³
Explanation:
Given data:
Initial volume of gas = 3.00 dm³
Initial pressure = 101 Kpa
Final pressure = 14.2 Kpa
Final volume = ?
Solution;
The given problem will be solved through the Boly's law,
"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"
Mathematical expression:
P₁V₁ = P₂V₂
P₁ = Initial pressure
V₁ = initial volume
P₂ = final pressure
V₂ = final volume
Now we will put the values in formula,
P₁V₁ = P₂V₂
101 Kpa × 3.00 dm³ = 14.2 Kpa × V₂
V₂ = 303 Kpa. dm³/ 14.2 Kpa
V₂ = 21.3 dm³
Explanation:
