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Ilia_Sergeevich [38]
3 years ago
10

How many milliliters of 0.130 M HCl are needed to completely neutralize 41.0 mL of 0.107 M Ba(OH)2 solution?

Chemistry
1 answer:
Anvisha [2.4K]3 years ago
3 0

54 mL Ba(OH)2x(0.101 mol Ba(OH)2/1000 mL) x (2 mol OH-/ 1 mol Ba(OH)2 )  = 0.0109 mol OH-

                                 

0.0109 mol OH-x (1mol HCl/ 1 mol OH- ) = 0.0109 mol HCl

                                                     

0.109 mol HCl/(0.130 mol/L HCl) =  0.0839 L HCl

0.0839 L HCl * 1000mL = 83.9 mL of 0.130 M HCl

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kompoz [17]

Answer: pH = 2,897 , basic[H+][OH-] = 10^{-14} ==> [H+] = \frac{10^{-14}}{7,89*10^{-12} } =\frac{1}{789} \\pH= -lg([H+]) = 2,897 \\pH basic

Explanation:

6 0
3 years ago
How much faster does ethane (C2H6) gas travel compared to chlorine gas?
zimovet [89]

Answer:

\large \boxed{\text{54 $\, \%$ faster }}

Explanation:

v_{\text{rms}} \propto \sqrt{\dfrac{3RT}{M}

if temperature is constant.  

v_{\text{rms}} \propto \sqrt{\dfrac{1}{M}

if we are comparing two gases,

\dfrac{v_{2}}{v_{1}} = \sqrt{\dfrac{M_{1}}{M_{2}}}

Let chlorine be Gas 1 and ethane be Gas 2

Data:

M₁ =  70.91 g/mol

M₂ = 30.07 g/mol

Calculation

\begin{array}{rcl}\dfrac{v_{2}}{v_{1}} & = & \sqrt{\dfrac{M_{1}}{M_{2}}}\\\\& = & \sqrt{\dfrac{70.91}{30.07}}\\\\& = & \sqrt{2.358}\\\\& = & \mathbf{1.54}\\\end{array}\\\text{Ethane molecules travel at 1.54 times the speed of chlorine molecules}\\\text{or $\large \boxed{\textbf{54 $\%$ faster }}$ than chlorine molecules}

5 0
3 years ago
Explain the centrifuging ​
Lynna [10]

Answer:the force from spinning that moves things away from the center

Explanation: ap chem

3 0
3 years ago
Need help setting the problem up
Sveta_85 [38]

Answer:

4.0 moles

Explanation:

The following data were obtained from the question:

Volume (V) = 12L

Pressure = 5.6 atm

Temperature (T) = 205K

Gas constant (R) = 0.08206 atm.L/Kmol

Number of mole (n) =?

Using the ideal gas equation: PV = nRT, the number of mole of the gas can be obtained as follow

PV = nRT

5.6 x 12 = n x 0.08206 x 205

Divide both side by 0.08206 x 205

n = (5.6 x 12)/(0.08206 x 205)

n = 4.0 moles

Therefore, the number of mole of the gas is 4.0 moles

5 0
3 years ago
Given 2Na + Cl2=2NaCl, what is the excess reactant? What is the limiting reactant?
QveST [7]

Answer: The limiting reactant is Na

Explanation:

5 0
3 years ago
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