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LekaFEV [45]
2 years ago
9

Briefly explain why experiments having faulty design or inconsistent data are problems for scientists. List several reasons

Physics
1 answer:
Readme [11.4K]2 years ago
8 0

Answer:

There are several reasons that experiments with faulty designs or with inconsistent data are problematic for scientists. A person can make one of those problems if he or she were to poorly measure what they are studying. For example, someone measured the mass of a book correctly to be 2 pounds, and someone else measured it mistakenly to be 1 pound. Another way that a person can make problems with faulty designs and inconsistent data is the lack of accuracy and precision. This could happen when someone can have the value of 10 from a correct data set of 9, 10, 10, 11, and 12, and someone else can have the value of 10 from an incorrect data set of 5, 7, 19, 15, and 10. The first data set has a lot more precision that the second data set. Another example would be: Someone could have the value of 10 from a correct data set of 9, and 11. Someone else can have the value of 10, but have the incorrect data of 7, and 15. The first set has more accuracy than the second set. A third reason that faulty designed experiments and inconsistent data can happen is the flawed experiments. For flawed experiments to happen, they may be uncontrolled, untrustworthy conclusions, or being inconsistent with other tests performed. For the last reason that they can happen, there can be bias. this could happen when the samples are too small, not randomly selected samples, and some outliers are present.

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Would it be true that if you double the distance of an astronaut from a planet, the gravitational pull between them would be hal
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Yes

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A 3.5 kg object moving in two dimensions initially has a velocity v1 = (12.0 i^ + 22.0 j^) m/s. A net force F then acts on the o
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Answer:

The work done by the force is 820.745 joules.

Explanation:

Let suppose that changes in potential energy can be neglected. According to the Work-Energy Theorem, an external conservative force generates a change in the state of motion of the object, that is a change in kinetic energy. This phenomenon is describe by the following mathematical model:

K_{1} + W_{F} = K_{2}

Where:

W_{F} - Work done by the external force, measured in joules.

K_{1}, K_{2} - Translational potential energy, measured in joules.

The work done by the external force is now cleared within:

W_{F} = K_{2} - K_{1}

After using the definition of translational kinetic energy, the previous expression is now expanded as a function of mass and initial and final speeds of the object:

W_{F} = \frac{1}{2}\cdot m \cdot (v_{2}^{2}-v_{1}^{2})

Where:

m - Mass of the object, measured in kilograms.

v_{1}, v_{2} - Initial and final speeds of the object, measured in meters per second.

Now, each speed is the magnitude of respective velocity vector:

Initial velocity

v_{1} = \sqrt{v_{1,x}^{2}+v_{1,y}^{2}}

v_{1} = \sqrt{\left(12\,\frac{m}{s} \right)^{2}+\left(22\,\frac{m}{s} \right)^{2}}

v_{1} \approx 25.060\,\frac{m}{s}

Final velocity

v_{2} = \sqrt{v_{2,x}^{2}+v_{2,y}^{2}}

v_{2} = \sqrt{\left(16\,\frac{m}{s} \right)^{2}+\left(29\,\frac{m}{s} \right)^{2}}

v_{2} \approx 33.121\,\frac{m}{s}

Finally, if m = 3.5\,kg, v_{1} \approx 25.060\,\frac{m}{s} and v_{2} \approx 33.121\,\frac{m}{s}, then the work done by the force is:

W_{F} = \frac{1}{2}\cdot (3.5\,kg)\cdot \left[\left(33.121\,\frac{m}{s} \right)^{2}-\left(25.060\,\frac{m}{s} \right)^{2}\right]

W_{F} = 820.745\,J

The work done by the force is 820.745 joules.

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