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LekaFEV [45]
2 years ago
9

Briefly explain why experiments having faulty design or inconsistent data are problems for scientists. List several reasons

Physics
1 answer:
Readme [11.4K]2 years ago
8 0

Answer:

There are several reasons that experiments with faulty designs or with inconsistent data are problematic for scientists. A person can make one of those problems if he or she were to poorly measure what they are studying. For example, someone measured the mass of a book correctly to be 2 pounds, and someone else measured it mistakenly to be 1 pound. Another way that a person can make problems with faulty designs and inconsistent data is the lack of accuracy and precision. This could happen when someone can have the value of 10 from a correct data set of 9, 10, 10, 11, and 12, and someone else can have the value of 10 from an incorrect data set of 5, 7, 19, 15, and 10. The first data set has a lot more precision that the second data set. Another example would be: Someone could have the value of 10 from a correct data set of 9, and 11. Someone else can have the value of 10, but have the incorrect data of 7, and 15. The first set has more accuracy than the second set. A third reason that faulty designed experiments and inconsistent data can happen is the flawed experiments. For flawed experiments to happen, they may be uncontrolled, untrustworthy conclusions, or being inconsistent with other tests performed. For the last reason that they can happen, there can be bias. this could happen when the samples are too small, not randomly selected samples, and some outliers are present.

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An organ pipe open at both ends has two successive harmonics with frequencies of 220 Hz and 240 Hz. What is the length of the pi
Harman [31]

Answer:

The  length is  l  =  8.6 \  m

Explanation:

From the question we are told that

   The frequencies of the two successive harmonics are f_1 =  220 \ Hz ,  f_2  =  240 \  Hz

   The speed of sound in the air is  v_s  =  343 \  m/s

Generally the frequency of a given harmonic is mathematically represented as

     f_n  =  \frac{n  v  }{2l}

Here  n defines  the position of the harmonics

Now since the position of both harmonic is not know but we know that they successive then we can represented them mathematically as

    220  =  \frac{n v}{2l}

and  

     240  =  \frac{(n+1) v}{2l}

So

   \frac{(n + 1 ) v}{2l} - \frac{n v}{2l}  =  240-220

=>  \frac{v}{2l}  =  20

=>   l  =  8.6 \  m

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