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Mariana [72]
3 years ago
6

3. A box contains 7 Green balls, 5 Red balls, and 3 Blue balls. A ball is randomly selected and its color is noted. Then it is r

eplaced into the same box A second ball is selected randomly and its color is noted. Find the probability of each of these questions: a Selecting 1 Blue ball and 1 Green ball. b. Selecting 1 Red ball and 1 blue ball​
Mathematics
1 answer:
ziro4ka [17]3 years ago
6 0

Answer:

a. 7/45

b. 1/15

Step-by-step explanation:

15 total balls

a. Selecting 1 Blue ball and 1 Green ball

3/15 * 7/15 = 21/225 = 7/45

b. Selecting 1 Red ball and 1 blue ball​

5/15 * 3/15 = 15/225 = 1/15

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This is an exponential decay problem.

Using the equation Y = a *(1-rate)^time

where Y is the future value given as 12,000 and a is the starting value given as 13,000.

The rate is also given as 5%.

The equation becomes:

12,000 = 13,000(1-0.05)^x

12,000 = 13,000(0.95)^x

Divide each side by 13000:

12000/13000 = 0.95^x/13000

12/13 = 0.95^x

Use the natural log function:

x = ln(12/13) / ln(0.95)

x = 1.56 years. ( this will equal 12,000

Round to 2 years it will be less than 12000.

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3 years ago
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Answer:

The sign would be positive.

The answer would be 144.

Step-by-step explanation:

Note that there are two negative numbers and two positive numbers:

positive x positive = positive answer.

negative x negative = positive answer.

Solve:

(-4) * (-3) = 12

2 * 6 = 12

12 * 12 = 144

144 would be your answer.

~

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3 years ago
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