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Mariana [72]
3 years ago
6

3. A box contains 7 Green balls, 5 Red balls, and 3 Blue balls. A ball is randomly selected and its color is noted. Then it is r

eplaced into the same box A second ball is selected randomly and its color is noted. Find the probability of each of these questions: a Selecting 1 Blue ball and 1 Green ball. b. Selecting 1 Red ball and 1 blue ball​
Mathematics
1 answer:
ziro4ka [17]3 years ago
6 0

Answer:

a. 7/45

b. 1/15

Step-by-step explanation:

15 total balls

a. Selecting 1 Blue ball and 1 Green ball

3/15 * 7/15 = 21/225 = 7/45

b. Selecting 1 Red ball and 1 blue ball​

5/15 * 3/15 = 15/225 = 1/15

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It gets more complicated with a six-sided die. In this case if you roll the die, there are 6 possible outcomes (1, 2, 3, 4, 5 or 6). Can you figure out what the theoretical probability for each number is? It is 1/6 or 0.17 (or 17 percent).

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Find the 15th term in the Arithmetic Sequence An = 3n-7
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The answer to this question is on my profile

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3 years ago
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S_A_V [24]

Answer:

Angle parking is more common than perpendicular parking.

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Step-by-step explanation:

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5 0
3 years ago
-(10(2)-2(8)+5(-1))​
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Answer:

1

Explanation:

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= −(4+−5)

= −(−1)

= 1

- Mordancy.

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