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3 years ago

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A radio station uses 1/6 of it's time for the news. In a 24 hour day, how many are used for music and entertainment? Wouldn't it

be 20 hours for music and entertainment?
Wouldn't it be 20 hours?

Since they used 4 hours for news, so 24 - 4 = 20 for music and entertainment?

Someone else is telling me it's 4 hours but I'm confused on their reasoning.

1 answer:

d1i1m1o1n [39]3 years ago

6 0

If they have 24 hours in a day, and use 1/6 of those 24 hours on news, they use 24*(1/6) or 4 hours on news. Assuming that they use the leftover time for just music and entertainment, we have 20h - 4h, so thats 20h. You were right. Not sure on their reasoning either.

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The length of the hypotenuse of the right triangle is 25 cm, the length of one of the legs is 10 cm. What is the length of the s

sergejj [24]

Answer:

$\large\boxed{AD=21\ and\ CD=2\sqrt{21}}$

Step-by-step explanation:

Look at the picture.

Use the Pythagorean theorem for calculate the length of CA:

$CA^2+CB^2=AB^2$

We have

$CA=x,\ CB=10,\ AB=25$

Substitute:

$x^2+10^2=25^2$

$x^2+100=625$ subtract 100 from both sides

$x^2=525\to x=\sqrt{525}\\\\x=\sqrt{25\cdot21}\\\\x=\sqrt{25}\cdot\sqrt{21}\\\\x=5\sqrt{21}\ cm$

ΔADC and ΔACB are similar. Therefore the corresponding sides are in proportion:

$\dfrac{AD}{AC}=\dfrac{AC}{AB}$

We have:

$AD=y,\ AC=5\sqrt{21},\ AB=25$

Substitute:

$\dfrac{y}{5\sqrt{21}}=\dfrac{5\sqrt{21}}{25}$

$\dfrac{y}{5\sqrt{21}}=\dfrac{\sqrt{21}}{5}$ cross multiply

$5y=5(\sqrt{21})^2$ divide both sides by 5

$y=21\ cm$

If you mean the length of segment CD, then use the proportion:

$\dfrac{CD}{AD}=\dfrac{CB}{CA}$

Substitute:

$\dfrac{CD}{21}=\dfrac{10}{5\sqrt{21}}\\\\\dfrac{CD}{21}=\dfrac{2}{\sqrt{21}}\qquad\text{cross multiply}\\\\CD\sqrt{21}=42\qquad\text{multiply both sides by}\ \sqrt{21}\\\\21CD=42\sqrt{21}\qquad\text{divide both sides by 21}\\\\CD=2\sqrt{21}\ cm$

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3 years ago

A board is 4 feet 8 inches long how long is the board inches

Otrada [13]

the board is 56 inches long.

how i did this was

12 * 4 = 48

48 + 8 = 56

<em>hope this helps :)</em>

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3 years ago

A square steel bar has a length of 5.1 ft and a 2.7 in by 2.7 in cross section and is subjected to axial tension. The final leng

Andrej [43]

Answer:

The Poisson's ratio for the material is 0.0134.

Step-by-step explanation:

The Poisson's ratio ( $\nu$ ), no unit, is the ratio of transversal strain ( $\epsilon_{t}$ ), in inches, to axial strain ( $\epsilon_{a}$ ), in inches:

$\nu = -\frac{\epsilon_{t}}{\epsilon_{a}}$ (1)

$\epsilon_{a} = l_{a,f}-l_{a,o}$ (2)

$\epsilon_{t} = l_{t,f}-l_{t,o}$ (3)

Where:

$l_{a,o}$ - Initial axial length, in inches.

$l_{a,f}$ - Final axial length, in inches.

$l_{t,o}$ - Initial transversal length, in inches.

$l_{t,f}$ - Final transversal length, in inches.

If we know that $l_{a,o} = 61.2\,in$ , $l_{a,f} = 61.235\,in$ , $l_{t,o} = 2.7\,in$ and $l_{t,f} = 2.69953\,in$ , then the Poisson's ratio is:

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$\epsilon_{t} = -4.7\times 10^{-4}\,in$

$\nu = - \frac{(-4.7\times 10^{-4}\,in)}{0.035\,in}$

$\nu = 0.0134$

The Poisson's ratio for the material is 0.0134.

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3 years ago

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Lelu [443]

A(b-c)
First substitute values
-8(12+4)=
Next, solve using ordering of PEMDAS
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Molodets [167]

Answer:

<h2>400</h2>

Step-by-step explanation:

$4\times10^6\text{ is how many times large than}\ 1 \times 10^4?\\\\\dfrac{4\times10^6}{1\times10^4}=\dfrac{4}{1}\times\dfrac{10^6}{10^4}=4\times10^{6-4}=4\times10^2=4\times100=400$

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3 years ago