All categories

3 years ago

0.15/0.5×(-0.16/1.2)

Mathematics

1 answer:

zzz [600]3 years ago

5 0

The got -0.04x I hope this helps

You might be interested in

PLEASE HeLp!!!!<br> Question BELow!

Law Incorporation [45]

I'm going to label them from top to bottom 1,2,3,4,5
your answer is 3,4,5,2,1

8 0

4 years ago

A sweatshirt is discounted 30%. If the discount is $9, what was the original price of the sweatshirt? Please show your work.

ArbitrLikvidat [17]

Answer:

$30

Step-by-step explanation:

Let the price of sweatshirt be $x.

Discount percentage = 30%

Discount in dollars = 30% of $x

Discount in dollars = 30/100 of $x = $ 30x/100

Given that discount in $ is 9

thus

30x/100 = 9

x = 9*100/30 = 30

Thus, the original price is $30

6 0

4 years ago

You are given the exponential function g(x)=3^x. Which ootion below gives the formula for the new function h created by stretchi

Citrus2011 [14]

Answer:

h(x) = 3^(x + 1)

Step-by-step explanation:

The exponential function is;

g(x) = 3^(x)

Now, in transformation of exponential functions of say f(x) = b^(x), when the new function g(x) is created by stretching by a factor of say c along the y-axis, we have;

g(x) = c•b^(x)

In this question, we are told it is stretched by a factor of 3 along the y-axis.

Thus, new function h is;

h(x) = 3 × 3^(x)

Using law of indices, we have;

h(x) = 3^(x + 1)

7 0

3 years ago

Help pleaseeeeeeeeeeeeeeeeeeeeeee

sasho [114]

Answer:

1/5 pound

I just did this on paper and got 1/5 pound (23/40)

6 0

3 years ago

Car X weighs 136 pounds more than car Z. Car Y weighs 117 pounds more than car Z. The total weight of all three cars is 9439 pou

Aleksandr [31]

Let x, y and z denote the weighs of car X, car Y and car Z, respectively.

We know that car X weighs 136 more than car Z, this can be express by the equation:

$x=z+136$

We also know that Y weighs 117 pounds more than car Z, this can be express as:

$y=z+117$

Finally, we know that the total weight of all the cars is 9439, then we have:

$x+y+z=9439$

Hence, we have the system of the equations:

$\begin{gathered} x=z+136 \\ y=z+117 \\ z+y+z=9439 \end{gathered}$

To solve the system we can plug the values of x and y, given in the first two equations, in the last equation; then we have:

$\begin{gathered} z+136+z+117+z=9439 \\ 3z=9439-136-117 \\ 3z=9186 \\ z=\frac{9186}{3} \\ z=3062 \end{gathered}$

Now that we have the value of z we plug it in the first two equations to find x and y:

$\begin{gathered} x=3062+136=3198 \\ y=3062+117=3179 \end{gathered}$

Therefore, car X weighs 3198 pound, car Y weighs 3179 pounds and car Z weighs 3062 pounds.

4 0

1 year ago