0.15/0.5×(-0.16/1.2)

bearhunter [10]

The solution to a given word problem by writing it as an equation is k = 253/232

<h3>Expressing word problems in mathematical forms:</h3>

The process of expressing word problems in mathematical forms takes a logical and chronological approach while taking the variables and arithmetic operations given into consideration.

From the given information, to express the word problem in mathematical form, we have:

253 = 232 × k
253 = 232k

Making k the subject of the equation, we have:

k = 253/232

Learn more about expressing word problems here:

brainly.com/question/10556265

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5 0

2 years ago

1. A report from the Secretary of Health and Human Services stated that 70% of single-vehicle traffic fatalities that occur at n

Nuetrik [128]

Using the binomial distribution, it is found that there is a 0.7215 = 72.15% probability that between 10 and 15, inclusive, accidents involved drivers who were intoxicated.

For each fatality, there are only two possible outcomes, either it involved an intoxicated driver, or it did not. The probability of a fatality involving an intoxicated driver is independent of any other fatality, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.
n is the number of trials.
p is the probability of a success on a single trial.

In this problem:

70% of fatalities involve an intoxicated driver, hence $p = 0.7$ .

A sample of 15 fatalities is taken, hence $n = 15$ .

The probability is:

$P(10 \leq X \leq 15) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15)$

Hence

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 10) = C_{15,10}.(0.7)^{10}.(0.3)^{5} = 0.2061$

$P(X = 11) = C_{15,11}.(0.7)^{11}.(0.3)^{4} = 0.2186$

$P(X = 12) = C_{15,12}.(0.7)^{12}.(0.3)^{3} = 0.1700$

$P(X = 13) = C_{15,13}.(0.7)^{13}.(0.3)^{2} = 0.0916$

$P(X = 14) = C_{15,14}.(0.7)^{14}.(0.3)^{1} = 0.0305$

$P(X = 15) = C_{15,15}.(0.7)^{15}.(0.3)^{0} = 0.0047$

Then:

$P(10 \leq X \leq 15) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15) = 0.2061 + 0.2186 + 0.1700 + 0.0916 + 0.0305 + 0.0047 = 0.7215$

0.7215 = 72.15% probability that between 10 and 15, inclusive, accidents involved drivers who were intoxicated.

A similar problem is given at brainly.com/question/24863377

5 0

2 years ago

A rectangular box has dimensions 0.045m, 0.034m, 0.01m. Calculate the volume of the box in cm³:

sergiy2304 [10]

Answer:

$15.75 {cm}^{3}$

Step-by-step explanation:

Convert m to cm,

0.045m =4.5cm

0.034m = 3.5cm

0.01m = 1cm

Volume = 4.5 cm × 3.5 × 1 = 15.75 cm3

5 0

2 years ago

If f(x) = -5-4 and g(x) = -3 -2 find (f-g)(x)

asambeis [7]

<u>Answer:</u>

The correct answer option is D. $-5^x+3x-2$

<u>Step-by-step-explanation:</u>

We are given the following two functions:

$f(x)=-5^x-4$

and

$g(x)= -3x-2$

We are to find $(f-g)(x)$ so we will subtract the function g from function f, arrange the like terms together and combine them like shown below to get:

$(f-g)(x) =(-5^x-4)-(-3x-2)$

$(f-g)(x)=-5^x-4+3x+2$

$(f-g)(x)=-5^x+3x-2$

Therefore, $(f-g)(x)$ is equal to $-5^x+3x-2$ so the correct answer option is D. $-5^x+3x-2$ .

5 0

3 years ago

For each graph below, state wether it represents a function.

Paul [167]

Answers:

Row 1: No, No, No

Row 2: Yes, Yes, Yes

===============================

Explanation:

Use the vertical line test. If it is at all possible to draw a single vertical line through more than one point on the relation curve, then the relation is not a function. This is because a function is only possible when any x input leads to exactly one y output.

So that's why graphs 1,2,3 are not functions, while graphs 4,5,6 are functions.

8 0

3 years ago