Answer:
- Mechanical advantages allows humans to perform tasks much easier in terms of the force they need to apply, but must always obey the conservation of energy.
- Mechanical advantage is a measure of the ratio of output force to input force in a system, used to analyze the forces in simple machines like levers and pulleys.
- A good example is pushing a heavy object up a ramp. It may be easier to push the object up a ramp instead of just lifting it up to the right height, but it takes a longer distance.
Explanation:
<h3>Hope it helps you!! </h3>
The answer is false because its a physical change
Answer:If each side of the equation has the same number of atoms of a given element, that element is balanced. If all elements are balanced, the equation is balanced. - online resource
Explanation: if not im sorry
Answer:
0.091 mol/L
Explanation:
Molarity of a substance , is the number of moles present in a liter of solution .
M = n / V
M = molarity ( unit = mol / L or M )
V = volume of solution in liter ( unit = L ),
n = moles of solute ( unit = mol ),
Moles is denoted by given mass divided by the molecular mass ,
Hence ,
n = w / m
n = moles ,
w = given mass ,
m = molecular mass .
From the data of the question , it is given that ,
w = 1.5 g
V = 220 mL
Since ,
1 mL = 1/1000L
V = 0.220 L
As we known , the mass of bleach NaOCl is ,
m = 74.44 g/mol
from the above equation , moles can be calculated as -
n = w / m
n = 1.5g / 74.44 g/mol
n = 0.0201 mol
Molarity of the solution is calculated as ,
M = n / V
M = 0.0201 mol / 0.220 L
M = 0.091 mol/L
Answer:
2SO₂(g) + O₂(g) ↔ 2SO₃(g) Kc = 15M⁻¹
The sets are:
(A) (SO₂)=0.16M; (O₂)=0.20M; (SO₃)=0.50M
(B) (SO₂)=0.20M; (O₂)=0.60M; (SO₃)=0.60M
(C) (SO₂)=0.50M; (O₂)=0.60M; (SO₃)=0.15M
The reaction quotient is
Q = ![\frac{[SO_{3}]^2}{[SO_{2}]^{2}*[O_{2}] }](https://tex.z-dn.net/?f=%5Cfrac%7B%5BSO_%7B3%7D%5D%5E2%7D%7B%5BSO_%7B2%7D%5D%5E%7B2%7D%2A%5BO_%7B2%7D%5D%20%7D)
- If Q < Kc, then the reaction will proceed towards the right (products)
- If Q > Kc, then the reaction will proceed towards the left (reactants)
- If Q = Kc, then we're at equilibrium.
Now we <u>calculate Q for each of the sets</u>:
(A) Q = 0.50² / (0.16²*0.20) = 48.8
Q > Kc. So the reaction will proceed towards the left.
(B) Q = 0.60² / (0.20²*0.60) = 15
Q = Kc. So the reaction is at equilibrium.
(C) Q = 0.15² / (0.50²*0.60) = 0.15
Q < Kc. So the reaction will proceed towards the right.
