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aksik [14]
3 years ago
15

Will give brainliest! What is the balanced equation for Mg+O2?

Chemistry
2 answers:
Anettt [7]3 years ago
8 0

Answer:

2Mg+O2 = 2MgO is the balanced equation of this reaction. When Mg +O2 reacts MgO is formed. The number of atoms of each element on reactant and product side must be equal

Explanation:

Ur welcome

pogonyaev3 years ago
6 0

Answer:

2Mg+O2 ⇒ 2MgO

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Only 9 I’m about to end it Jesus
igor_vitrenko [27]

Answer:

Ok so the answer for 9 is

x/6=4

x=24

Explanation:

Solve for x by simplifying both sides of the equation, then isolating the variable.

7 0
3 years ago
The decomposition of N_2O_5(g) following 1st order kinetics. N_2O_5(g) to N_2O_4(g) + ½ O_2(g) If 2.56 mg of N_2O_5 is initially
Crank

Answer: The rate constant is 0.334s^{-1}

Explanation ;

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = ?

t = age of sample  = 4.26 min

a =  initial amount of the reactant  = 2.56 mg

a - x = amount left after decay process  = 2.50 mg

Now put all the given values in above equation to calculate the rate constant ,we get

4.26=\frac{2.303}{k}\log\frac{2.56}{2.50}

k=\frac{2.303}{4.26}\log\frac{2.56}{2.50}

k=5.57\times 10^{-3}min^{-1}=5.57\times 10^{-3}\times 60s^{-1}=0.334s^{-1}

Thus rate constant is [tex]0.334s^{-1}

4 0
3 years ago
Oh, no! You just spilled 85.00 mL of 1.500 M sulfuric acid on your lab bench and need to clean it up immediately! Right next to
vredina [299]

Explanation:

We will balance equation which describes the reaction between sulfuric acid and sodium bicarbonate: as follows.

   H_2SO_4(aq) + 2NaHCO_3(s) \rightarrow Na2SO_4(aq) + 2H_2O(l) + 2CO_2(g)

Next we will calculate how many moles of H_2SO_4 are present in 85.00 mL of 1.500 M sulfuric acid.

As,       Molarity = \frac{\text{moles of solute}}{\text{liters of solution
}}

            1.500 M = \frac{n}{0.08500 L
}

                    n = 0.1275 mol H_2SO_4

Now set up and solve a stoichiometric conversion from moles of H_2SO_4  to grams of NaHCO_3. As, the molar mass of NaHCO_3 is 84.01 g/mol.

 0.1275 mol H_2SO_4 \times (\frac{2 mol NaHCO_3}{1 mol H_2SO_4}) \times (\frac{84.01 g NaHCO_3}{1 mol NaHCO_3})

                 = 21.42 g NaHCO_3

So unfortunately, 15.00 grams of sodium bicarbonate will "not" be sufficient to completely neutralize the acid. You would need an additional 6.42 grams to complete the task.

4 0
3 years ago
Describe at least two methods to separate a mixture of small copper and iron beads
bekas [8.4K]
<span>A fast way to separate the mixture would be to use a magnet. Iron is magnetic while copper is not. The second method would be to visually separate them since iron and copper distinctly different colors.</span>
3 0
3 years ago
Read 2 more answers
Enter the chemical formula of a binary molecular compound of hydrogen and a Group 6A element that can reasonably be expected to
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Answer:

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Explanation:

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3 0
3 years ago
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