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bagirrra123 [75]
3 years ago
10

What do elements in the same column in the periodic table have in common?

Chemistry
1 answer:
erastova [34]3 years ago
8 0
They have the same amount of valence electrons
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What is the pH of a solution with an [H+] of (a) 5.4 x 10-10, (b) 4.3 x 10-5, (c) 5.4 x 10-7?
IgorLugansk [536]

Answer:

a. 9.2

b. 4.4

c. 6.3

Explanation:

In order to calculate the pH of each solution, we will use the definition of pH.

pH = -log [H⁺]

(a) [H⁺] = 5.4 × 10⁻¹⁰ M

pH = -log [H⁺] = -log 5.4 × 10⁻¹⁰ = 9.2

Since pH > 7, the solution is basic.

(b) [H⁺] = 4.3 × 10⁻⁵ M

pH = -log [H⁺] = -log 4.3 × 10⁻⁵ = 4.4

Since pH < 7, the solution is acid.

(c) [H⁺] = 5.4 × 10⁻⁷ M

pH = -log [H⁺] = -log 5.4 × 10⁻⁷ = 6.3

Since pH < 7, the solution is acid.

3 0
2 years ago
Write a balanced chemical equation for the formation of magnesium oxide, mg0, from magnesium and oxygen
swat32
This picture explains:

7 0
3 years ago
9. What is the name of the molecule?
AnnyKZ [126]

Answer:

3–methyl–2–butanol

Explanation:

To name the compound, we must:

1. Identify the functional group.

2. Give the functional group of the compound the lowest possible count.

3. Locate the longest continuous carbon chain. This gives the parent name of the compound.

4. Identify the substituent group attached.

5. Give the substituent group the lowest possible count.

6. Combine the above to get the name of the compound.

Now, let us obtain the name of the compound.

1. The functional group of the compound is Alcohol i.e —OH.

2. The functional group is located at carbon 2.

3. The longest continuous carbon chain is carbon 4 i.e butane. But the presence of the functional group i.e OH will replace the –e in butane with –ol. Therefore, the compound is butanol.

4. The substituent group attached is methyl i.e CH3.

5. The substituent group is located at carbon 3.

6. Therefore, the name of the compound is:

3–methyl–2–butanol.

8 0
3 years ago
Which particle is emitted when an atom of 85Kr spontaneously decays?
stiv31 [10]
A Beta particles is emitted when an atom of 85Kr spontaneously decays.
5 0
3 years ago
Read 2 more answers
What is the kinetic energy of a 478 kg object that is moving with a speed of 15m/s
AVprozaik [17]

Answer:Kinetic energy = (1/2)*mass*velocity^2

KE = (1/2)mv^2

KE = (1/2)(478)(15)^2

KE = 53775J

Explanation:

Kinetic energy = (1/2)*mass*velocity^2

KE = (1/2)mv^2

KE = (1/2)(478)(15)^2

KE = 53775J

8 0
2 years ago
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