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Oksanka [162]
2 years ago
11

6. Add the following numbers together and show your answer in grams:

Chemistry
1 answer:
Verdich [7]2 years ago
8 0
I hope it helps, make sure of the answer before answering

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Tris has a molecular weight of 121 g/mol. How many grams of Tris would you need to make 100 mL of a 100 mM solution of Tris
Zepler [3.9K]

Answer:

1.21 g of Tris

Explanation:

Our solution if made of a solute named Tris

Molecular weight of Tris is 121 g/mol

[Tris] = 100 mM

This is the concentration of solution:

(100 mmoles of Tris in 1 mL of solution) . 1000

Notice that mM = M . 1000  We convert from mM to M

100 mM . 1 M / 1000 mM = 0.1 M

M = molarity (moles of solute in 1 L of solution, or mmoles of solute in 1 mL of solution). Let's determine the mmoles of Tris

0.1 M = mmoles of Tris / 100 mL

mmoles of Tris = 100 mL . 0.1 M → 10 mmoles

We convert mmoles to moles → 10 mmol . 1mol / 1000mmoles = 0.010 mol

And now we determine the mass of solute, by molecular weight

0.010 mol . 121 g /mol = 1.21 g

8 0
3 years ago
The element X has three naturally occurring isotopes. The masses (amu) and % abundances of the isotopes are given in the table b
denis-greek [22]

Answer:

220.42098 amu

Explanation:

(220 .9 X  .7422) + (220 X .0.1278) + (218.1 X 0.13) =     220.42098 amu

These are weighted averages.

So, we will take mass of one and multiply by abundance percentage that is provided and add them together.

In order to calculate the  average atomic mass, we have to convert the percentages of abundance to decimals. So, you get

(220 .9 X  .7422) + (220 X .0.1278) + (218.1 X 0.13) =     220.42098 amu

6 0
3 years ago
When your heart doesn't know what it wants.. what do you do?
DENIUS [597]
Follow your nose to the fruity taste of chows recharge the heart then follow your heart good luck my friend

3 0
3 years ago
Using the following reaction:
Romashka-Z-Leto [24]

Answer:

Mn is the oxidizing agent.

N is the reducing agent.

Explanation:

Hello!

In this case, according to the undergoing chemical reaction, it is seen that the manganese in KMnO4 has an oxidation state of 7+, in MnSO4 of 2+ and nitrogen in KNO2 is 3+ and in KNO3 is 5+; thus we have the following half-reactions:

Mn^{7+}+5e^-\rightarrow Mn^{2+}\\\\N^{3+}\rightarrow N^{5+}+2e^-

Thus, since manganese is undergoing a decrease in the oxidation state, we infer it is the oxidizing agent whereas nitrogen, undergoing an increase in the oxidation state is the reducing agent.

Best regards!

5 0
3 years ago
If you set up an experiment with two different independent variables, then the results would be_____.
MariettaO [177]

Answer: A) Inconclusive; you would not know which of the two variables caused the change.

Explanation:

When you set up an experiment, you must make sure that you control the variables such that only one independent variable changes at a time, while all the remainder conditions (the other independent variables) are controlled (fixed).

By observing (measuring) the dependent variable, while only one independent variable changes you can understandhow such independent variable explains (determines) the dependent variable, leading to a conclusion.

Conversely, if two or more independent variables change at a time, then there is no way that you can tell how the output (dependent variable) is related with one or other of the changes of the indipendent variables. You wolud not be able to discriminate (distinguish) the effect of one or other variable, making the experiment inconclusive

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4 0
3 years ago
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