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3 years ago

If y varies inversely as x, and y = 5 as x = -2, find y for the x-value of 3.

2 answers:

6 0

Since y varies inversely to x
xy = k
so 5*-2 = -10

plug x and k into xy = k

-10 = 3y
divide both sides with 3
y = -10/3 or -3.3333

sergiy2304 [10]3 years ago

5 0

Y varies inversly as x means
y=k/x

k is constantt
find k

so
5=k/-2
times -2 both sides
-10=k

y=-10/x

when x=3

y=-10/3

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Solve the equation.

Nutka1998 [239]

Answer:

Step-by-step explanation:

In this technique, if we have to factorise an expression like ax2+bx+c, we need to think of 2 numbers such that:

N1⋅N2=a⋅c=1⋅−12=−12

AND

N1+N2=b=−1

After trying out a few numbers we get N1=3 and N2=−4

3⋅−4=−12, and 3+(−4)=−1

x2−x−12=x2−4x+3x−12

x(x−4)+3(x−4)=0

(x+3)(x−4)=0

Now we equate the factors to zero.

x+3=0,x=−3

x−4=0,x=4

3 0

3 years ago

The formula V=Bh, where B represents the area of the base, can be used to find the volume of a cylinder. Which formula is equiva

Karo-lina-s [1.5K]

Answer:

Explanation:

B=Base Area

In a cylinder, the base area is a circle.

Area Circle=pi r^2

Replace base area with area of circle:

V=pi r^2 H

7 0

3 years ago

Read 2 more answers

What is 6 more than 7 times a number is 41

son4ous [18]

the problem would be set up as 6+(7*x)=41

first u take off the number 6 by subtracting it from itself to cancel it out then u do the same to the number 41

7x =41 now u need to cancel out the number 7 attatched to the x so u divikde it by itself and then do the same to the other side so 41 divided by 7 =5.9

so x =5.9

8 0

3 years ago

I don’t understand how to identify quadratic transformations. Can I have so help please?

Levart [38]

Answer:

The parent function for a quadratic is f(x) = x^2. If there is something other than this, that is how you know it is a quadratic transformation.

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2 years ago

A store selling newspapers orders only n = 4 of a certain newspaper because the manager does not get many calls for that publica

umka2103 [35]

Answer:

a) The expected value is 2.680642

b) The minimun number of newspapers the manager should order is 6.

Step-by-step explanation:

a) Lets call X the demanded amount of newspapers demanded, and Y the amount of newspapers sold. Note that 4 newspapers are sold when at least four newspaper are demanded, but it can be <em>more</em> than that.

X is a random variable of Poisson distribution with mean $\mu = 3$ , and Y is a random variable with range {0, 1, 2, 3, 4}, with the following values

PY(k) = PX(k) = ε^(-3)*(3^k)/k! for k in {0,1,2,3}
PY(4) = 1 -PX(0) - PX(1) - PX(2) - PX (3)

we obtain:

PY(0) = ε^(-3) = 0.04978..

PY(1) = ε^(-3)*3^1/1! = 3*ε^(-3) = 0.14936

PY(2) = ε^(-3)*3^2/2! = 4.5*ε^(-3) = 0.22404

PY(3) = ε^(-3)*3^3/3! = 4.5*ε^(-3) = 0.22404

PY(4) = 1- (ε^(-3)*(1+3+4.5+4.5)) = 0.352768

E(Y) = 0*PY(0)+1*PY(1)+2*PY(2)+3*PY(3)+4*PY(4) = 0.14936 + 2*0.22404 + 3*0.22404+4*0.352768 = 2.680642

The store is <em>expected</em> to sell 2.680642 newspapers

b) The minimun number can be obtained by applying the cummulative distribution function of X until it reaches a value higher than 0.95. If we order that many newspapers, the probability to have a number of requests not higher than that value is more 0.95, therefore the probability to have more than that amount will be less than 0.05

we know that FX(3) = PX(0)+PX(1)+PX(2)+PX(3) = 0.04978+0.14936+0.22404+0.22404 = 0.647231

FX(4) = FX(3) + PX(4) = 0.647231+ε^(-3)*3^4/4! = 0.815262

FX(5) = 0.815262+ε^(-3)*3^5/5! = 0.91608

FX(6) = 0.91608+ε^(-3)*3^6/6! = 0.966489

So, if we ask for 6 newspapers, the probability of receiving at least 6 calls is 0.966489, and the probability to receive more calls than available newspapers will be less than 0.05.

I hope this helped you!

8 0

3 years ago