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2 years ago

G=ta−F3 haha its shows GTA

Mathematics

2 answers:

DaniilM [7]2 years ago

6 0

Answer:

hEEHEE

Step-by-step explanation:

kogti [31]2 years ago

3 0

Hahaha but wait hold up is this an actual question?

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The primeter of a rectangle is 53 meters. The length is 2.3 meters longer than the width, w. Write and solve an equation to ind

lys-0071 [83]

The perimeter is the total of adding all of the sides together. A rectangle has 2 lengths and 2 widths. The equation would be:

P = 2l + 2w or P = l + l + w + w

Since you know the perimeter, you can plug it into the equation

53 = 2l + 2w

You can divide the 2 on both sides

26.5 = l + w

l = w + 2.3 because the length is 2.3 meters longer/more than the width. You can substitute (w + 2.3) for "l" in the equation. So instead of:

26.5 = l + w

It will be:

26.5 = (w + 2.3) + w

26.5 = w + 2.3 + w

Subtract 2.3 on both sides

24.3 = w + w

24.3 = 2w

Divide 2 on both sides

12.1 = w

The width is 12.1 meters

6 0

2 years ago

To decrease the impact on the environment, factory chimneys must be high enough to allow pollutants to dissipate over a larger a

Komok [63]

Answer:

The probability hat the sample mean height for the 40 chimneys is greater than 102 meters is 0.1469.

Step-by-step explanation:

Let the random variable X be defined as the height of chimneys in factories.

The mean height is, μ = 100 meters.

The standard deviation of heights is, σ = 12 meters.

It is provided that a random sample of n = 40 chimney heights is obtained.

According to the Central Limit Theorem if we have an unknown population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.

Then, the mean of the distribution of sample means is given by,

$\mu_{\bar x}=\mu$

And the standard deviation of the distribution of sample means is given by,

$\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}$

Since the sample selected is quite large, i.e. n = 40 > 30, the central limit theorem can be used to approximate the sampling distribution of sample mean heights of chimneys.

$\bar X\sim N(\mu_{\bar x},\ \sigma^{2}_{\bar x})$

Compute the probability hat the sample mean height for the 40 chimneys is greater than 102 meters as follows:

$P(\bar X>102)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}})>\frac{102-100}{12/\sqrt{40}})$

$=P(Z>1.05)\\=1-P(Z$

*Use a z-table fr the probability.

Thus, the probability hat the sample mean height for the 40 chimneys is greater than 102 meters is 0.1469.

8 0

2 years ago

Someone help me plz !!!!!

Mrac [35]

Answer:

£1 = 25 hits

Step-by-step explanation:

Will get the equation is

$\frac{40}{1000} = \frac{1}{x}$

so, X=25

x = What we want to find

4 0

2 years ago

Luna mixes 3/4 cup of orange juice with 3/8 cup of cranberry juice. She gives 5/8 cup of juice to mags. How much is left in luna

Debora [2.8K]

Answer:

The answer is 1/2

Step-by-step explanation:

First you must the least common denominator so that you can add the two fractions. The least common denominator between 3/4 and 3/8, would be 8.

To get 3/4 to the least common denominator, you have to multiply top and bottom by 2. The product of this will be 6/8.

Next you add the two fractions: 6/8 + 3/8 = 9/8

Simplify your improper fraction to get on and 1 eighths or in number form 1 1/8

After this you must subtract how much she gave away so you can use your improper fraction to make it easier and subtract five eighths from nine eighths: 9/8 - 5/8 = 4/8

So, Luna has four eighths of a glass left but first you must simplify your answer. both 4 and 8 divide by 4 to get 1/2.

So Luna's glass only has 1/2 in the cup.

Make sure you be optimistic and see it as half full, instead of the pessimistic view of half empty. Remember to stay positive and share good vibes. Hope this answer helps you.

4 0

2 years ago

A fish tank contains 18 goldfish and 22 guppies. If you randomly select 2 fish, what is the probability that they are both goldf

Leya [2.2K]

The total number of fish available in the tank is (18 + 22) = 40. The probability for 1 goldfish to be taken out would be 18/40. Now, after drawing the first fish, the probability to get another goldfish would be 17/39. And the probability to draw 2 goldfish would be the product of both probabilities. P = (18/40)(17/39) = 51/260 So,the answer is B.

3 0

2 years ago

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