<span>(6k+10) (4k+5) is not an equation. Or, did you unintentionally leave off "=0?"
Thus, we cannot find a value for k.
If we set </span><span>(6k+10) (4k+5) = to 0, then the roots would be solutions of 6k+10=0 and 4k+5=0. They are {-5/3, -5/4}</span>
Answer:
14n^2.
Step-by-step explanation:
This is Arithmetic with first term a = 14 and common difference d = 28.
Sum of n terms = n/2[2a + (n-1)d]
= n/2(28 +( n -1)28]
= n/2(28 + 28n - 28)
= 14n^2
Answer:
Step-by-step explanation:
We know that tangent angle addition formula is
This is in form already. Based on the value, a is 65 and b is 35 so let just subtract that
W e know that tan 30 is
Answer is 10(2k+5)
-----------------------------------
Work Shown:
20k+50 = 10*2k + 10*5
20k+50 = 10(2k+5)
Note how we can distribute the 10 back in to check our work
10(2k+5) = 10(2k)+10(5) = 20k+50
so that confirms we have the right answer
Another thing to notice is that 10 is the largest factor that we can pull out of 20k and 50. The value 10 is the GCF (greatest common factor) of 20 and 50.
