1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Hoochie [10]
3 years ago
8

2. An element is all the way through,​

Chemistry
1 answer:
elena55 [62]3 years ago
6 0
?? Is that the whole question?
You might be interested in
Calculate the solubility product constant, Ksp, of lead(II) chloride, PbCl2, which has a
V125BC [204]

Answer:

0.0159m

Explanation:

9 M

Explanation:

Lead(II) chloride,  

PbCl

2

, is an insoluble ionic compound, which means that it does not dissociate completely in lead(II) cations and chloride anions when placed in aqueous solution.

Instead of dissociating completely, an equilibrium rection governed by the solubility product constant,  

K

sp

, will be established between the solid lead(II) chloride and the dissolved ions.

PbCl

2(s]

⇌

Pb

2

+

(aq]

+

2

Cl

−

(aq]

Now, the molar solubility of the compound,  

s

, represents the number of moles of lead(II) chloride that will dissolve in aqueous solution at a particular temperature.

Notice that every mole of lead(II) chloride will produce  

1

mole of lead(II) cations and  

2

moles of chloride anions. Use an ICE table to find the molar solubility of the solid

 

PbCl

2(s]

 

⇌

 

Pb

2

+

(aq]

 

+

 

2

Cl

−

(aq]

I

 

 

 

−

 

 

 

 

 

0

 

 

 

 

 

0

C

 

 

x

−

 

 

 

 

(+s)

 

 

 

 

(

+

2

s

)

E

 

 

x

−

 

 

 

 

 

s

 

 

 

 

 

2

s

By definition, the solubility product constant will be equal to

K

sp

=

[

Pb

2

+

]

⋅

[

Cl

−

]

2

K

sp

=

s

⋅

(

2

s

)

2

=

s

3

This means that the molar solubility of lead(II) chloride will be

4

s

3

=

1.6

⋅

10

−

5

⇒

s

=  √ 1.6 4 ⋅ 10 − 5  = 0.0159 M

8 0
3 years ago
Except for speed, your nervous system is most similar to
dlinn [17]

Your nervous system is most similar to a cruise ship (option C).

The nervous system is a complex network in the body in charge of:

  • Automatic responses and movements.
  • Voluntary movements.
  • Responses to the world.

This system works due to the action of structures such as:

  • The brain.
  • The spinal cord.
  • The nerves.

Moreover, the nervous system works through the following steps:

  1. A stimulus is received, for example, you accidentally touch a hot surface.
  2. This is taken by the nerves to the brain.
  3. The brain processes the information and sends a response, for example, to move the hand away from the hot surface.

Based on this, the system resembles a cruise ship because signals go from the senses to the brain and then back again similar to a cruise going away and then back to the port.

Learn more about brain in: brainly.com/question/5361122

8 0
2 years ago
Normally the systemic arterial blood has a po2 of about _____ mm hg, a pco2 of about _____ mm hg, and a ph of _____.
erica [24]
Normally the systemic arterial blood has a pO₂ of about 75-100 mmHg, a pCO₂ of about 35-45 mmHg, and a pH of 7,35-7,45.
4 0
3 years ago
Diffrent between bryophytes and pteriodphytes
Pie
I would help if i could im sorry im sure someone else will answer soon im honestly trying to help as many people as i can
4 0
3 years ago
A 20.0-milliliter sample of 0.200 M K2CO3 solution is added to 30.0 milliliters of 0.400 M Ba(NO3)2 solution.
jenyasd209 [6]

Answer:

(B) 0.160 M

Explanation:

Considering:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Or,

Moles =Molarity \times {Volume\ of\ the\ solution}

Given :

For K_2CO_3 :

Molarity = 0.200 M

Volume = 20.0 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 20.0×10⁻³ L

Thus, moles of K_2CO_3 :

Moles=0.200 \times {20.0\times 10^{-3}}\ moles

Moles of K_2CO_3 = 0.004 moles

For Ba(NO_3)_2 :

Molarity = 0.400 M

Volume = 30.0 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume =30.0×10⁻³ L

Thus, moles of Ba(NO_3)_2 :

Moles=0.400\times {30.0\times 10^{-3}}\ moles

Moles of Ba(NO_3)_2  = 0.012 moles

According to the given reaction:

K_2CO_3_{(aq)}+Ba(NO_3)_2_{(aq)}\rightarrow BaCO_3_{(s)}+2KNO_3_{(aq)}

1 mole of potassium carbonate react with 1 mole of barium nitrate

0.004 moles potassium carbonate react with 0.004 mole of barium nitrate

Moles of barium nitrate  = 0.004 moles

Available moles of barium nitrate  =  0.012 moles

Limiting reagent is the one which is present in small amount. Thus, potassium carbonate is limiting reagent.

The formation of the product is governed by the limiting reagent. So,

1 mole of potassium carbonate gives 1 mole of barium carbonate

Also,

0.004 mole of potassium carbonate gives 0.004 mole of barium carbonate

Mole of barium carbonate = 0.004 moles

Also, consumed barium nitrate = 0.004 moles  (barium ions precipitate with carbonate ions)

Left over moles = 0.012 - 0.004 moles = 0.008 moles

Total volume = 20.0 + 30.0 mL = 50.0 mL = 0.05 L

So, Concentration = 0.008/0.05 M = 0.160 M

<u>(B) is correct.</u>

4 0
3 years ago
Other questions:
  • Which ideal solution exhibits the greatest osmotic pressure?
    12·1 answer
  • Suppose the half life of an isotope is 30 seconds and you have 10 grams to start with how much will you have after one minute
    15·1 answer
  • What is the role of neutrons in an atom??
    8·2 answers
  • PLEASE HELP!!!! I am so lost
    6·1 answer
  • 19. Why is slow-freezing so damaging to food compared to fast freezing?
    9·1 answer
  • What is the energy of an electromagnetic wave with a electromagnetic wave with a frequency of 3 * 10 Hz ?
    12·1 answer
  • 3 points
    6·1 answer
  • Perform the following mathematical operation, and report the answer to the correct number of significant figures.
    13·1 answer
  • Identify the following elements based on the information provided:
    8·1 answer
  • What kind of scientist forms new materials by studying chemical reactions?
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!