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GalinKa [24]
3 years ago
12

How many different isomers can be derived from ethylene if two hydrogen atoms are replaced by a fl uorine atom and a chlorine at

om? draw their structures and name them. indicate which are structural isomers and which are geometric isomers?

Chemistry
1 answer:
svp [43]3 years ago
8 0
Answer:
             THREE<span> different isomers can be derived from ethylene if two hydrogen atoms are replaced by a fl uorine atom and a chlorine atom.

Explanation:
                   When two Hydrogen atoms in ethylene (C</span>₂H₄) are replaced with Fluorine and Chlorine atom then the new molecular formula is C₂H₂FCl.
                    Compounds having same Molecular formula but different structural formula are called as Isomers.
                     First Isomer of C₂H₂FCl is 1-chloro-1-fluoroethene, in which F and Cl at geminal position (attached to same Carbon atom).
                     Other two Isomers are Geometrical Isomers of 1-chloro-2-fluoroethene, in which F and Cl at different carbon atom and having different position is space. The one in which both F and Cl at opposite side forms (<em>trans</em>)-1-chloro-2-fluoroethene and the one in which both are in same side is called as (<em>cis</em>)-1-chloro-2-fluoroethene.

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Assuming constant pressure, rank these reactions from most energy released by the system to most energy absorbed by the system,
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B)-61.9 kJ

Explanation:

The change in the internal energy of a system  is positive if the reaction absorbs energy and  negative if the reaction releases energy. For a system to cause an increase in volume, it must have very high energy built up to be released.

1. Surroundings get colder and the system decreases in volume. Here, the surrounding absorbs energy  resulting in positive  ΔE

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4. Surroundings get hotter and the system does not change in volume.  System is negative because it releases energy even thgoygh there is no change in volume

Therefore the order from the Most energy released to most Energy   Absorbed Is given as  2---> 4--->,3-->---> 1

b) Using  

 ΔE = q+ w     from 1st law of thermodynamics

 ΔE=  ΔH - P  ΔV

gIven  

 ΔH = -75.0KJ

volume=  A change  from 5.0L TO 2.0L = Final volume - initial volume = 2-5= -3.00L

P= 43.0atm

ΔE=  ΔH - P  ΔV

P  ΔV  = 43 atm x -3 = -129L.atm

We first convert  L-atm to Joules.

1 L-atm = 101.325 Joules.  

129L.atm = 129 x 101.325 = - 13071 J

to KJ becomes

13071/1000 = - 13.071KJ

Recall ΔE=  ΔH - P  ΔV and putting values

ΔE  = -75.0 - (-13.071 KJ)= -75.0 kJ + 13.071 kJ = -61.9 kJ

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