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Delicious77 [7]
3 years ago
5

BASED ON THE INFORMATION BELOW. CALCULATE THE MASS FOR ONE OF THESE ATOMS:

Chemistry
1 answer:
stepladder [879]3 years ago
7 0

C = 12 g

O = 16 g

H = 1 g

<h3>Further explanation </h3>

Conservation of mass stated that  

<em>In a closed system, the masses before and after the reaction are the same </em>

we can calculate the mass of each atom in the compound :

O in O₂ :

mass O₂ = 32

mass O = 32 : 2 = 16 g

H in H₂O

mass H₂O = 18

mass 2.H + mass O = 18

mass 2.H + 16 = 18

mass 2.H=2

mass H = 1 g

C in CH₄

mass CH₄ = 16

mass C + mass 4.H = 16

mass C + 4.1=16

mass C = 12 g

or we can use formula :

Mass of a single C :

\tt =\dfrac{Ar~C}{MW~CO_2}\times mass~CO_2\\\\=\dfrac{12}{44}\times 44=12

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3 years ago
22.4l of ammonia is reaxts with 1.406 mole of oxygen to produce NO and h2o .1.what volume of no is produced at ntp​
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Answer:

The volume of NO is 22.4L at STP

Explanation:

Based on the reaction:

2NH3 + 5/2O2 → 2NO + 3H2O

<em>2 moles of NH3 react with 5/2 moles of O2 to produce 2 moles of NO.</em>

<em />

To solve this question, we need to find the moles of each reactant in order to find the limiting reactant as follows:

<em>Moles NH3 -Molar mass: -17.01g/mol-</em>

Using PV = nRT

PV/RT = n

<em>Where P is pressure = 1atm at STP</em>

<em>V is volume = 22.4L</em>

<em>R is gas constant = 0.082atmL/molK</em>

<em>T is absolute temperature = 273.15K</em>

1atm*22.4L/0.082atmL/molK*273.15K = n

n = 1.00 moles of NH3

For a complete reaction of 1.00 moles of NH3 are needed:

1.00 moles NH3 * (5/2moles O2 / 2moles NH3) = 1.25 moles of O2

As there are 1.406 moles of O2, <em>the limiting reactant is NH3</em>

<em />

The moles of NO produced are the same than moles of NH3 because 2 moles of NH3 produce 2 moles of NO. The moles of NO are 1.00 moles

And as 1.00moles of gas are 22.4L at STP:

<h3>The volume of NO is 22.4L at STP</h3>

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2 years ago
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6 0
3 years ago
Read 2 more answers
2. Extract the relevant information from the question: NaOH V = 30 mL , M = 0.10 M HCl V = 25.0 mL, M = ?
Andrei [34K]

Answer:

0.12M

Explanation:

A balanced equation for the reaction will go a great deal in obtaining our desired result. So, let us write a balanced equation for the reaction

HCl + NaOH —> NaCl + H2O

From the above equation,

nA (mole of the acid) = 1

nB (mole of the base) = 1

Data obtained from the question include:

Vb (volume of the base) = 30mL

Mb (Molarity of the base) = 0.1M

Va (volume of the acid) = 25mL

Ma (Molarity of the acid) =?

The molarity of the acid can be obtained as follow:

MaVa/MbVb = nA/nB

Ma x 25/ 0.1 x 30 = 1

Cross multiply to express in linear form

Ma x 25 = 0.1 x 30

Divide both side by 25

Ma = (0.1 x 30) / 25

Ma = 0.12M

The molarity of the acid is 0.12M

5 0
3 years ago
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