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Delicious77 [7]
3 years ago
5

BASED ON THE INFORMATION BELOW. CALCULATE THE MASS FOR ONE OF THESE ATOMS:

Chemistry
1 answer:
stepladder [879]3 years ago
7 0

C = 12 g

O = 16 g

H = 1 g

<h3>Further explanation </h3>

Conservation of mass stated that  

<em>In a closed system, the masses before and after the reaction are the same </em>

we can calculate the mass of each atom in the compound :

O in O₂ :

mass O₂ = 32

mass O = 32 : 2 = 16 g

H in H₂O

mass H₂O = 18

mass 2.H + mass O = 18

mass 2.H + 16 = 18

mass 2.H=2

mass H = 1 g

C in CH₄

mass CH₄ = 16

mass C + mass 4.H = 16

mass C + 4.1=16

mass C = 12 g

or we can use formula :

Mass of a single C :

\tt =\dfrac{Ar~C}{MW~CO_2}\times mass~CO_2\\\\=\dfrac{12}{44}\times 44=12

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Explanation:

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The elements of group two shows +2 charge because these all alkali metals and lose their two valance electrons.

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Group 3:

The elements of group three-B shoes +3 charge by losing three valance electrons.

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The elements of group 4th A and 4th B lose four electrons or gain four electrons to complete the octet and shows +4 or -4 charge.

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It involve the elements of group 5th A.

Group 6:

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3 years ago
Barium sulfate is made by the following reaction.
ipn [44]

Answer:

                      %age Yield =   96 %

Explanation:

                    The balance chemical equation for given double replacement reaction is,

                      Ba(NO₃)₂ + Na₂SO₄ → BaSO₄ + 2 NaNO₃

Step 1: <u>Calculate moles of Ba(NO₃)₂:</u>

Moles  =  Mass / M.Mass

Moles  =  75.1 g / 261.33 g/mol

Moles  =  0.2873 moles of Ba(NO₃)₂

Step 2: <u>Find out moles of BaSO₄ formed:</u>

According to balance chemical equation,

                  1 mole of Ba(NO₃)₂ produced  =  1 mole of BaSO₄

So,

        0.2873 moles of Ba(NO₃)₂ will produce  =  X moles of BaSO₄

Solving for X,

                      X =  0.2873 mol × 1 mol / 1 mol

                       X =  0.2873 moles of BaSO₄

Step 3: Calculate Theoretical Mass of BaSO₄:

Mass  =  Moles × M.Mass

Mass  =  0.2873 mol × 233.38 g/mol

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Step 4: <u>Calculate %age Yield as:</u>

                 Theoretical Yield  =  67.07 g

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                  %age Yield  =  <u>???</u>

Formula Used:

                   %age Yield  =  (Actual Yield ÷ Theoretical Yield) × 100

Putting Values,

                   %age Yield  =  (64.4 g ÷ 67.07 g) × 100

                   %age Yield =  96.01 % ≈ 96 %

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