Answer:
Explanation:
Given that ;
Compound H is optically active and have a molecular formula of C6H10 and therefore undergo catalytic hydrogenation. Catalytic hydrogenation involves the use Platinum/Nickel to produce C6H12
i.e

The proposed H and I structures are shown in the diagrams attached below .
compound H represents 3- methyl cyclopentene
compound I represents methyl cyclopentane
However; 3- methyl cyclopentene posses just only one chiral carbon which is optically active at the third position and it R and S enantiomers are shown in the second diagram below.
Answer:
+1.76 V
Explanation:
Ecell = Ecathode - Eanode
= -0.19 - (-1.95) = + 1.76 V
Answer:
The correct answer is - they can create genetic diversity as well and reproduce without mate when necessary.
Explanation:
Sexual reproduction provides an organism with genetic diversity and variation by the process and it required two mates and a longer time to pollination and fertilization and is used in normal conditions.
In case of a threat, such organisms use asexual reproduction to increase their number as in asexual reproduction no need of mate, an organism can grow and increase on its own it provides to not to exitinct.