Question

454 grams of isomaltitol, C12H24O11, was combusted in a furnace completely in an excess oxygen. The products of this reaction are water and carbon dioxide. What is the theoretical yield (in kilograms) of water produced from this reaction?

Answer 1

The theoretical yield (in kilograms) of water produced from this reaction : 0.285 kg

Further explanation

Reaction

2C₁₂H₂₄O₁₁ + 25O₂ → 24CO₂ + 24H₂O

mass of C₁₂H₂₄O₁₁ - isomaltitol = 454 g

mol C₁₂H₂₄O₁₁(MW=344.31 g/mol) :

$\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{454}{344.31 g/mol}\\\\mol=1.319$

mol H₂O based on C₁₂H₂₄O₁₁ as limiting reactant(O₂-oxygen as an excess)

From the equation above, mol ratio of C₁₂H₂₄O₁₁  : H₂O = 2 : 24, so mol H₂O:

$\tt mol~H_2O=\dfrac{24}{2}\times 1.319=15.828$

then mass H₂O (MW=18 g/mol) :

$\tt mass=mol\times MW\\\\mass=15.828\times 18=284.904~g=0.285~kg$