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ycow [4]
3 years ago
6

454 grams of isomaltitol, C12H24O11, was combusted in a furnace completely in an excess oxygen. The products of this reaction ar

e water and carbon dioxide. What is the theoretical yield (in kilograms) of water produced from this reaction?
Chemistry
1 answer:
sergij07 [2.7K]3 years ago
3 0

The theoretical yield (in kilograms) of water produced from this reaction : 0.285 kg

<h3>Further explanation</h3>

Reaction

2C₁₂H₂₄O₁₁ + 25O₂ → 24CO₂ + 24H₂O

mass of C₁₂H₂₄O₁₁ - isomaltitol = 454 g

mol C₁₂H₂₄O₁₁(MW=344.31 g/mol) :

\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{454}{344.31 g/mol}\\\\mol=1.319

mol H₂O based on C₁₂H₂₄O₁₁ as limiting reactant(O₂-oxygen as an excess)

From the equation above, mol ratio of C₁₂H₂₄O₁₁  : H₂O = 2 : 24, so mol H₂O:

\tt mol~H_2O=\dfrac{24}{2}\times 1.319=15.828

then mass H₂O (MW=18 g/mol) :

\tt mass=mol\times MW\\\\mass=15.828\times 18=284.904~g=0.285~kg

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Katarina [22]

<u>Answer:</u> The new pressure will be 101.46 kPa.

<u>Explanation:</u>

To calculate the new pressure, we use the equation given by Gay-Lussac Law. This law states that pressure is directly proportional to the temperature of the gas at constant volume.

The equation given by this law is:

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

P_1\text{ and }T_1 are initial pressure and temperature.

P_2\text{ and }T_2 are final pressure and temperature.

We are given:

By using conversion factor:   T(K)=T(^oC)+273

P_1=108kPa\\T_1=41^oC=314K\\P_2=?kPa\\T_2=22^oC=295K

Putting values in above equation, we get:

\frac{108kPa}{314K}=\frac{P_2}{295K}\\\\P_2=101.46kPa

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4 0
3 years ago
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