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Naya [18.7K]
3 years ago
5

Choose the substance with the lowest viscosity. choose the substance with the lowest viscosity. f2chchf2 f2chch2f fch2ch2f f3cch

f2 f3ccf3
Chemistry
2 answers:
Maksim231197 [3]3 years ago
7 0

Answer : FCH_{2}CH_{2}F

Explanation : In the molecule of FCH_{2}CH_{2}F  the hydrogen bonding forces tend to resist any phase transition form liquid state to gaseous phase, and these hydrogen bonding forces are greater  usually when the hydrogen is bound to an electronegative atom like chlorine, fluorine,oxygen,etc. This then lowers the viscosity of the compound.

Viktor [21]3 years ago
7 0

The substance with lowest viscosity is \boxed{{\text{FC}}{{\text{H}}_{\text{2}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{F}}}.

Further explanation:

Viscosity is defined as the resistance of any liquid to flow. Stronger the intermolecular forces of attraction within the liquid, larger will be its viscosity.

Intermolecular forces:

The forces that exist between the molecules are known as intermolecular forces (IMF). They are electrostatic in nature and determine the bulk properties of the substances like melting and boiling points. Molecules are held in any substance due to these forces.

The various types of intermolecular forces are as follows:

1. Hydrogen bonding.

2. Ion-dipole forces.

3. Ion-induced dipole forces.

4. Dispersion forces

Hydrogen bonding:  

It is an attractive force that exists between hydrogen and more electronegative elements like N, O, F. It can either be intermolecular or intramolecular. Intermolecular hydrogen bonding is the one that occurs between different molecules. For example, the bond between HF and {{\text{H}}_{\text{2}}}{\text{O}} is an intermolecular hydrogen bond. Intramolecular hydrogen bonding occurs between various parts of the same molecule. Ortho-nitro phenol and salicylaldehyde show this type of bonding.

With an increase in the number of fluorine atoms in the compound, the polarity of the compound increases. Due to increase in polarity of compound, the tendency to form hydrogen bonds with water molecules also increases and that is the reason for increase in viscosity or the compound.

{{\text{F}}_{\text{3}}}{\text{CHCH}}{{\text{F}}_{\text{3}}} has the highest number of fluorine atoms among all the compounds, so it has highest tendency to form hydrogen bonding that attributes to its highest viscosity.

{\text{FC}}{{\text{H}}_{\text{2}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{F}} has lowest number of fluorine atoms among all the compounds, so it has lowest tendency to form hydrogen bonding that attributes to its lowest viscosity.

Learn more:

1. Determination of kinetic energy of the emitted electrons when cesium is exposed to UV rays:  

shttps://brainly.com/question/5031462

2. At what gas temperature would the average translational kinetic energy of a helium atom be equal to that of an oxygen molecule: brainly.com/question/9924094

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Kinetic Energy

Keywords: Kinetic energy, viscosity, intermolecular forces, hydrogen bonding, electronegative, fluorine, polarity, and hydrogen.

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(40 Points) Complete, balance, compute the amounts of the products assuming 100% yield. 12g Zinc Solid + 24g Silver Nitrate
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Answer:

Zn + 2AgNO₃ → Zn(NO₃)₂ +2Ag

13.34g Zn(NO₃)₃ and 15.24g Ag are formed if reaction is 100% complete.

Explanation:

molar mass of Zn=65 g

molar mass of AgNO₃=170 g

molar mass of Zn(NO₃)₂ =189  g

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Zn + 2  AgNO₃ → Zn(NO₃)₂ +2 Ag            eq(1)

1 mole Zn  reacts with 2 moles Silver nitrate to give 1 mole Zinc nitrate and 2 moles Silver

or

65 g Zn reacts with 2×170 g of AgNO₃  → 189 g Zn(NO₃)₂ and 2×108 g Ag    - eq(2)

First find limiting reagent of the reaction

65g Zn reacts with 2×170g of AgNO₃

12 g Zn reacts with (12÷65)×2×170 g AgNO₃

=62.7 g AgNO₃

For the reaction to go to 100% yield 12 g Zn will need 62.7 g AgNO₃

but amount of AgNO₃ is 24 g

So the reaction yields is limited by amount of AgNO₃.

AgNO₃ is the limiting reagent.

So calculate the yield of products with the amount of AgNO₃

by eq(2)

2× 170 gAgNO₃ gives 189 g Zn(NO₃)₃

=340 g AgNO₃ gives 189 g Zn(NO₃)₃

24 g AgNO₃ gives (24÷340) ×189 g Zn(NO₃)₃

=13.34g Zn(NO₃)₃

again by eq2

2×170 g AgNO₃ gives 2×108 g Ag

= 340 g AgNO₃ gives 216 g Ag

24 g AgNO₃ gives (24÷340)×216 g Ag

= 15.24g Ag

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