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Black_prince [1.1K]
3 years ago
10

How do i draw a growth triangle for the problem y= 2x-3? I have to find M and B

Mathematics
1 answer:
professor190 [17]3 years ago
3 0
Well m is 2 and b is 3
Using the equation y=Mx+B
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Determine which equations below, when combined with the equation 3x-4y=2, would form a system with no solutions. Choose all that
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The question is in the picture
GrogVix [38]

Ten-thousand   AFAFANDIUAHDIUAHIUDHAIDh (had to write 20 more "letters")


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What are the diffrent ways to write a ratio pls help​
Viefleur [7K]

One way to write a ratio is 5:8 or 5 to 8 and <u>5</u>

                                                                         8

4 0
3 years ago
Which point would be a solution to the system of linear inequalities ?
brilliants [131]

Answer:

(12,-6)

Step-by-step explanation:

we have

y\leq \frac{4}{3}x+5 ----> inequality A

y\geq -\frac{5}{2}x+5 ---> inequality B

we know that

If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities (makes true both inequalities)

<u><em>Verify each point</em></u>

Substitute the value of x and the value of y  of each ordered pair in the inequality A and in the inequality B

case 1) (0,-1)

Inequality A

-1\leq \frac{4}{3}(0)+5

-1\leq5 ----> is true

Inequality B

-1\geq -\frac{5}{2}(0)+5

-1\geq 5 ----> is not true

therefore

The ordered pair is not a solution of the system

case 2) (0,3)

Inequality A

3\leq \frac{4}{3}(0)+5

3\leq5 ----> is true

Inequality B

3\geq -\frac{5}{2}(0)+5

3\geq 5 ----> is not true

therefore

The ordered pair is not a solution of the system

case 3) (-6,-6)

Inequality A

-6\leq \frac{4}{3}(-6)+5

-6\leq-3 ----> is true

Inequality B

-6\geq -\frac{5}{2}(-6)+5

-6\geq 20----> is not true

therefore

The ordered pair is not a solution of the system

case 4) (12,-6)

Inequality A

-6\leq \frac{4}{3}(12)+5

-6\leq21 ----> is true

Inequality B

-6\geq -\frac{5}{2}(12)+5

-6\geq -25 ----> is true

therefore

The ordered pair is a solution of the system (makes true both inequalities)

8 0
3 years ago
Coefficient of x^2 in expansion of (x+2)^5
iVinArrow [24]
The x² term will be C(5,2)x²·2³ = 80x².

The coefficient is 80.

_____
C(n, k) = n!/(k!·(n-k)!)
C(5, 2) = 5·4/(2·1) = 10
8 0
3 years ago
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