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SOVA2 [1]
3 years ago
10

What is the degree of this polynomial? 5 + 2s

Mathematics
1 answer:
garri49 [273]3 years ago
3 0
<h3>Answer:  1</h3>

=====================================================

Explanation:

We can rewrite 5 as 5s^0, since s^0 = 1 where s is nonzero.

Think of 2s as 2s^1

With those ideas in mind, the original polynomial turns into 5s^0 + 2s^1

Sorting the terms so that the largest exponent is first gets us the standard form 2s^1 + 5s^0

The largest exponent is the degree, so the degree is 1.

Side note: This trick only works for single variable polynomials.

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Two packages weigh 3.92 pounds and 2.8 pounds. How many times heavier Is the first package than the second?
avanturin [10]

3.92/2.8=1.4

Unless it’s reverse.

2.8/3.92=0.714285714285 and so on.

3 0
4 years ago
12x + 8 + 84 = 15х +9
RideAnS [48]

Answer:

x = 83/3.

Step-by-step explanation:

12x + 8 + 84 = 15х +9

Solving for x:

8 + 84 - 9 = 15x - 12x

83 = 3x

x = 83/3.

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3 years ago
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4 years ago
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Elenna [48]

Answer:

2

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8 0
2 years ago
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1. A circle with center (-5, 2) is tangent to the y-axis. What is the radius of the circle? What is the equation of the circle?
Bess [88]

Answer:

Step-by-step explanation:

1)  The center lies on the vertical line x = -5 and the the circle is tangent to (touches in one place only) the y-axis.  Thus, the radius is 5.

2)  Starting with (x - h)^2 + (y - k)^2 = r^2 and comparing this to the given

                     (x - 4)^2 + (y + 3)^2 = 6^2

we see that h = 4, k = -3 and r = 6.  The center is at (4, -3) and the radius is 6.

3)  Notice that A and B have the same x-coordinate, x = 15.  The center of the circle is thus (15, -2), where that -2 is the halfway point between the two given points in the vertical direction.   Arbitrarily choose A(15, 4) as one point on the circle.  Then the equation of this circle is

(x - 4)^2 + (y + 3)^2 = r^2 = 6^2, where the 6 is one half of the vertical distance between A(15, 4) and B(15, -8) (which is 12).

4 0
3 years ago
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