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2 years ago

How to tell cold fronts from warm fronts

1 answer:

3 0

If cold air is advancing into warm air, a cold front is present. On the other hand, if a cold air mass is retreating and warm air is advancing, a warm front exists. Otherwise, a stationary front is present if the cold air is neither advancing nor retreating from the warm air mass.

This it’s from a textbook so it might be copyright so re-word (please mark me has brainlyest)

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What are the three ways acceleration can occur

Mariana [72]

Answer:

Change in velocity, change in direction, change in both velocity and direction

Explanation:

5 0

2 years ago

The graph above shows the position x as a function of time for the center of mass of a system of particles of total mass 6. 0 kg

kumpel [21]

The resulting change in momentum of the system will be +18.6 Ns. The momentum is conserved.

<h3>What is the law of conservation of momentum?</h3>

According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.

The given data in the problem is;

m is the mass =6.0 kg

t is the time interval=2 second

From Newton's second law;

$\rm \triangle P =m \triangle V \\\\ \triangle P= m(\frac{\triangle x}{\triangle t} )\\\\$

From the graph;

$\rm \triangle t = 2sec\\\\ \triangle x = (12-8) m$

The change in the momentum is;

$\rm \triangle P = m\tr(\frac{v-u}{t}) \\\\ \triangle P =9.3 \times \frac{12-8}{2} \\\\ \triangle P= +18.6 \ N.s$

Hence, the resulting change in momentum of the system will be +18.6 Ns.

To learn more about the law of conservation of momentum, refer;

brainly.com/question/1113396

#SPJ1

6 0

1 year ago

Which statement accurately describes the relationship between force and momentum?

ivann1987 [24]

Answer:

Explanation:

momentum depends on weight and speed

4 0

2 years ago

How fast is the spaceship traveling towards the Sun? The radius of the orbit of Jupiter is 43.2 light-minutes, and that of the o

melisa1 [442]

Question:

A spaceship enters the solar system moving toward the Sun at a constant speed relative to the Sun. By its own clock, the time elapsed between the time it crosses the orbit of Jupiter and the time it crosses the orbit of Mars is 35.0 minutes

How fast is the spaceship traveling towards the Sun? The radius of the orbit of Jupiter is 43.2 light-minutes, and that of the orbit of Mars is 12.6 light-minutes.

Answer:

S = 5.508 × 10¹¹m

V = 2.62 × 10⁸ m/s

Explanation:

The radius of the orbit of Jupiter, Rj is 43.2 light-minutes

radius of the orbit of Mars, Rm is 12.6 light-minutes

Distance travelled S = (Rj - Rm)

= 43.2 - 12.6 = 30.6 light- minutes

= 30.6 × (3 ×10⁸m/s) × 60 s

= 5.508 × 10¹¹m

time = 35mins = (35 × 60 secs)

= 2100 secs

speed = distance/time

V = 5.508 × 10¹¹m / 2100 s

V = 2.62 × 10⁸ m/s

7 0

3 years ago

a body is thrown vertically upward from the earth's surface and it took 8 seconds to return to its original position . find out

Mnenie [13.5K]

Answer:

The initial velocity with which the body was thrown up is 39.2 m/s

Explanation:

The given parameters for the body are;

The time it takes the body to return back to its initial position = 8 seconds

To answer the question, we make use of the kinematic equation of motion, v = u - g·t

Where

v = The final velocity of the body = 0 m/s at the maximum height

u = The initial velocity

g = The acceleration due to gravity = 9.8 m/s²

t = The time in which the body spends in the air

Therefore, at maximum height, we have;

v = 0 = u - g·t

u = g·t

t = u/g

From h = 1/2gt², which gives t = √(2·h/g), the time the body takes to maximum height = The time the body takes to return to its original position from maximum height.

Therefore, the total time in which the body is in the air = 2 × t = 2× u/g

∴

The total time in which the body is in the air = The time it takes the body to return back to its initial position after being thrown = 2 × t = 8 seconds

∴ 2 × t = 8 s = 2 × u/g

8 s = 2 × u/g

u = (8 s × g)/2

∴ u = (8 s × 9.8 m/s²)/2 = 39.2 m/s

The initial velocity with which the body was thrown up = u = 39.2 m/s.

4 0

2 years ago