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motikmotik
3 years ago
10

Have you heard of any particle, which moves faster than light? Explore the recent researches and find about it.

Physics
1 answer:
Lisa [10]3 years ago
4 0

Answer:

There is nothing faster then light

Explanation:

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A +27 nCnC point charge is placed at the origin, and a +6 nCnC charge is placed on the xx axis at x=1mx=1m. At what position on
svet-max [94.6K]

Answer:

The position on the x axis is 0.32 m.

Explanation:

Given that,

Point charge = 27 nC

Charge = 6 nC

Distance = 1

We need to calculate the distance

Using formula of electric field

\dfrac{kq_{1}}{x^2}=\dfrac{kq_{2}}{(r-x)^2}

Put the value into the formula

\dfrac{27\times10^{-9}}{x^2}=\dfrac{6\times10^{-9}}{(1-x)^2}

\dfrac{27}{x^2}=\dfrac{6}{(1-x)^2}

\dfrac{(1-x)^2}{x^2}=\dfrac{27}{6}

\dfrac{1-x}{x}=\sqrt{\dfrac{27}{6}}

\dfrac{1}{x}=\sqrt{\dfrac{27}{6}}+1

x=0.32\ m

Hence, The position on the x axis is 0.32 m.

5 0
2 years ago
In which place moutain or terai,the value of g is more and why?​
PolarNik [594]

Answer:

the radius of the earth in himalayan region is greater than terai reagion. therefore, the value of 'g' at the poles is greater than the value of g at the equator. 12

Explanation:

plz mark as brainlist thx :)

6 0
3 years ago
The larger the push, the larger the change in velocity. This is an example of Newton's Second Law of Motion which states that th
Mars2501 [29]

Answer:

According to Newton's 2nd law

The force acting on a body produces acceleration in its direction which is directly propotional to the force but inversly propotinal to the mass of tbe body.

Explanation:

a = F/m

F = ma

Where( F) is force (m) is mass and (a) is acceleration.

6 0
3 years ago
A car with a mass of 600 kg is traveling at a velocity of 10 m/s. How much kinetic energy does it have?
Viefleur [7K]

Answer:

KE = 30,000 J

Explanation:

KE = \frac{1}{2} mv²

KE = \frac{1}{2} (600)(10)²

KE = \frac{1}{2} (600)(100)

KE = \frac{1}{2} (60000)

KE = 30,000 J

5 0
3 years ago
Concept Simulation 20.4 provides background for this problem and gives you the opportunity to verify your answer graphically. Ho
77julia77 [94]

Answer:

The time constant is 1.049.

Explanation:

Given that,

Charge q{t}= 0.65 q_{0}

We need to calculate the time constant

Using expression for charging in a RC circuit

q(t)=q_{0}[1-e^{-(\dfrac{t}{RC})}]

Where, \dfrac{t}{RC} = time constant

Put the value into the formula

0.65q_{0}=q_{0}[1-e^{-(\dfrac{t}{RC})}]

1-e^{-(\dfrac{t}{RC})}=0.65

e^{-(\dfrac{t}{RC})}=0.35

-\dfrac{t}{RC}=ln (0.35)

-\dfrac{t}{RC}=-1.049

\dfrac{t}{RC}=1.049

Hence, The time constant is 1.049.

6 0
3 years ago
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