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3 years ago

Help meee, if u help me i give u a pizza :)

Chemistry

1 answer:

kompoz [17]3 years ago

6 0

Give me 25 minutes and I’ll have the answers :)

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How many electrons are in the n = 2 shell of a magnesium atom?

Montano1993 [528]

Answer:

eight

Explanation:

That means there are 12 electrons in a magnesium atom

hope this helps

8 0

2 years ago

4) How many moles of O2 are produced with 42.0 moles of H2O?

grandymaker [24]

Answer:

1.2353 mol

Explanation:

3 0

3 years ago

Calculate the molar mass of a gas

spin [16.1K]

Answer:

MOLAR MASS = 32 g/mol

Explanation:

Condition of standard temperature and pressure(STP) are as follow:

Temperature = 273 K

Pressure = 1 atm (or 100000 Pa)

Here atm is atmosphere and Pa is Pascal

STP conditions arte used for measuring gas density and volume using Ideal Gas Law.Here 1 mole of ideal gas occupies 22.4 L of volume.

According toi Ideal Gas Equation :

PV = nRT

where P = pressure, n= number of moles, V = volume ,R= Ideal Gas Constant and T= temperature

$n=\frac{PV}{RT}$

From question:

V=280 ml = 0.28 L

P = 1 atm

R=0.08205 L atm/K mol

T=273 K

Putting values in above formula :

$n=\frac{1\times .280}{0.08205\times 273}$

n = 0.0125 moles

Now $n=\frac{given\ mass}{Molar\ mass}$

$Molar\ mass=\frac{given\ mass}{n}$

given mass = 0.4 g (given)

$Molar\ mass=\frac{0.4}{0.0125}$

On solving we get:

Molar mass = 32 g/mol

4 0

3 years ago

The density of gold is 19.3 the density of iron pyrite is 5.0 if a nugget of iron pyrite and a nugget of gold each have a mass o

exis [7]

Density equals mas divided by volume. You know the density and mass so use it to solve for the volume.

d= m/v
d= 19.3 g/mL
m= 50g
v=?

Plug it in. 19.3= 50/v

To solve for v you do the opposite of 50 divided by v which is 50 time v.
That cancels v from the right side of the equation. Do the same on the other side(times v)
19.3 * v=50

Now just divide both sides by 19.3 to get v alone.

7 0

3 years ago

A mixture initially contains A, B, and C in the following concentrations: [A] = 0.650 M, [B] = 1.35 M, and [C] = 0.300 M. The fo

dimaraw [331]

Answer: The value of $K_c$ for given reaction is 0.465