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horsena [70]
3 years ago
15

The solid anhydrous solid CoCl2 is blue in color. Because it readily absorbs water from the air, it is used as a humidity indica

tor to monitor if equipment (such as a cell phone) has been exposed to excessive levels of moisture. Predict what product is formed by this reaction, and how many unpaired electrons this complex will have.
Chemistry
1 answer:
MrRissso [65]3 years ago
6 0

Answer:

CoCl_{2}.(H_{2}O)_{6} is formed and it has three unpaired electrons.

Explanation:

Blue CoCl_{2} reacts with water to produce pink colored CoCl_{2}.(H_{2}O)_{6} complex.

In this complex, Co^{2+} ion forms an octahedral complex with six H_{2}O ligands.

As H_{2}O is a weak field ligand therefore Co^{2+} ion remains in low spin state.

Hence electronic configuration of Co^{2+} ion in this octahedral geometry is t_{2g}^{5}e_{g}^{2} with total three unpaired electrons.

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During science lab, Jacob mixes together sodium hydroxide (NaOH) and hydrochloric acid (HCl). The two chemicals react to form so
Svet_ta [14]
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3 years ago
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13. What does 2n^2 stand for?
Sever21 [200]

Answer:

2n² is a formula that determines that the maximum number of electrons should be accommodated in a particular shell.

Explanation:

4 0
2 years ago
What is the mass, in grams, of 2.50 * 10-3 mol of aluminum sulfate?
Nonamiya [84]

Answer:

The mass is 0.855 grams (option A)

Explanation:

Step 1: Data given

aluminium sulfate = Al2(SO4)3

Numer of moles Al2(SO4)3 = 2.50 * 10^-3 moles

atomic mass Al = 26.99 g/mol

atomic mass S = 32.065 g/mol

Atomic mass O = 16 g/mol

Step 2: Calculate molar mass Al2(SO4)3

Molar mass = 2* 26.99 + 3*32.065 + 12*16

Molar mas = 342.175 g/mol

Step 3: Calculate mass Al2(SO4)3

Mass Al2(SO4)3 = moles Al2(SO4)3 * molar mass Al2(SO4)3

Mass Al2(SO4)3 = 2.5 *10^-3 moles * 342.175 g/mol

Mass Al2(SO4)3 = 0.855 grams

The mass is 0.855 grams (option A)

5 0
3 years ago
Find the mass of 3.27 x 10^23 molecules of H2SO4. Use 3 significant digits<br> and put the units.
marta [7]

Answer:

Approximately 53.3\; \rm g.

Explanation:

Lookup Avogadro's Number: N_{\rm A} = 6.02\times 10^{23}\; \rm mol^{-1} (three significant figures.)

Lookup the relative atomic mass of \rm H, \rm S, and \rm O on a modern periodic table:

  • \rm H: 1.008.
  • \rm S: 32.06.
  • \rm O: 15.999.

(For example, the relative atomic mass of \rm H is 1.008 means that the mass of one mole of \rm H\! atoms would be approximately 1.008\! grams on average.)

The question counted the number of \rm H_2SO_4 molecules without using any unit. Avogadro's Number N_{\rm A} helps convert the unit of that count to moles.

Each mole of \rm H_2SO_4 molecules includes exactly (1\; {\rm mol} \times N_\text{A}) \approx 6.02\times 10^{23} of these \rm H_2SO_4 \! molecules.

3.27 \times 10^{23} \rm H_2SO_4 molecules would correspond to \displaystyle n = \frac{N}{N_{\rm A}} \approx \frac{3.27 \times 10^{23}}{6.02 \times 10^{23}\; \rm mol^{-1}} \approx 0.541389\; \rm mol of such molecules.

(Keep more significant figures than required during intermediary steps.)

The formula mass of \rm H_2SO_4 gives the mass of each mole of \rm H_2SO_4\! molecules. The value of the formula mass could be calculated using the relative atomic mass of each element:

\begin{aligned}& M({\rm H_2SO_4}) \\ &= (2 \times 1.008 + 32.06 + 4 \times 15.999)\; \rm g \cdot mol^{-1} \\ &= 98.702\; \rm g \cdot mol^{-1}\end{aligned}.

Calculate the mass of approximately 0.541389\; \rm mol of \rm H_2SO_4:

\begin{aligned}m &= n \cdot M \\ &\approx 0.541389\; \rm mol \times 98.702\; \rm g \cdot mol^{-1}\\ &\approx 53.3\; \rm g\end{aligned}.

(Rounded to three significant figures.)

6 0
3 years ago
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