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AnnyKZ [126]
2 years ago
11

Enter the net ionic equation for the reaction of aqueous sodium chloride with aqueous silver nitrate.

Chemistry
2 answers:
natita [175]2 years ago
8 0

The net ionic equation: Ag⁺ (aq) + Cl⁻(aq) -> AgCl (s)

<h3>Further explanation </h3>

The electrolyte in the solution produces ions.

The equation of a chemical reaction can be expressed in the equation of the ions

For strong electrolytes (the ionization rate = 1) is written in the form of separate ions, while the weak electrolyte (degree of ionization <1) is still written as an un-ionized molecule

In the ion equation, there is an ion spectator that is the ion which does not react because it is present before and after the reaction

When these ions are removed, the ionic equation is called the net ionic equation

For gases and solids including water (H₂O) can be written as an ionized molecule

So only the dissolved compound is ionized ((expressed in symbol aq)

Formation of precipitating compounds that cause reactions can occur from double-replacement reactions

Solubility Rules:

  • 1. soluble compound

All compounds of Li⁺, Na⁺, K⁺, Rb⁺, Cs⁺, and NH₄⁺

All compounds of NO₃⁻ and C₂H₃O₂⁻

Compounds of Cl⁻, Br⁻, I⁻ except Ag⁺, Hg₂²⁺, Pb²⁺

Compounds of SO₄²⁻ except Hg₂²⁺, Pb²⁺, Sr²⁺, Ba²⁺

  • 2. insoluble compounds

Compounds of CO₃²⁻ and PO₄³⁻ except for Compounds of Li +, Na +, K +, Rb +, Cs +, and NH₄ +

Compounds of OH− except Compounds of Li +, Na +, K +, Rb +, Cs +, NH₄⁺, Sr²⁺, and Ba²⁺

The reaction between AgNO₃ (aq) and NaCl (aq)

AgNO₃ (aq) + NaCl (aq) ⇒AgCl (s) + NaNO₃ (aq)

AgCl is an insoluble compound, so reactions can take place and double-replacement reactions occur

Complete ion reaction:

\rm Ag ^ ++ NO_3 ^ - + Na ^ ++ Cl ^ -  \Rightarrow AgCl (s) + Na ^ ++ NO_3 ^ - \\\\ spectator \: ions: Na ^ + \: and \ : NO_3 ^ - \\\\ net \: ionic \: equation: Ag ^ ++ Cl ^ - \Rightarrow AgCl (s)

<h3>Learn more </h3>

the net ionic equation

brainly.com/question/8885824

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Ksivusya [100]2 years ago
6 0

An ionic equation refers to a chemical equation where the electrolytes in aqueous solution are demonstrated as dissociated ions. Generally, this is a salt dissolved in water, where the ionic species are succeeded by (aq) in the equation, to suggest that they are in aqueous solution.  

Net ionic equation refers to a chemical equation for a reaction that lists only those species that takes part in the reaction. It is an equation, which demonstrates only the reactants taking part in the formation of a precipitate.  

In the given case, balanced chemical equations is,  

AgNO₃ (aq) + NaCl (aq) = AgCl (s) + NaNO₃ (aq)

Complete ionic equation:  

Ag⁺ (aq) +NO₃⁻ (aq) + Na⁺ (aq) + Cl⁻ (aq) = AgCl (s) + Na⁺ (aq) + NO₃⁻ (aq)

Net Ionic equation:  

Ag⁺ (aq) + Cl⁻ (aq) = AgCl (s) (Silver chloride settles as white precipitate)


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Answer:

41.11 g of Ca(OH)2.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

CaO + H2O —> Ca(OH)2

Next, we shall determine the masses of CaO and H2O that reacted and the mass of Ca(OH)2 produced from the balanced equation. This can be obtained as follow:

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Mass of CaO from the balanced equation = 1 × 56 = 56 g

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Mass of H2O from the balanced equation = 1 × 18 = 18 g

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From the balanced equation above,

56 g of CaO reacted with 18 g of H2O to produce 74 g of Ca(OH)2.

Finally, we obtained the mass of calcium hydroxide, Ca(OH)2 produced from the reaction of 33 g of CaO and 10 g of H2O. This can be obtained as follow:

From the question given above, we were told that when 33 g of CaO and 10 g of H2O reacted, 2 g of CaO were remaining. This implies that H2O is the limiting reactant and CaO is the excess reactant.

Thus, we shall use the limiting reactant to determine the mass of calcium hydroxide, Ca(OH)2 produced because it will give the maximum yield as all of it is consumed in the reaction.

The limiting reactant is H2O and the mass of calcium hydroxide, Ca(OH)2 produced can be obtained as follow:

From the balanced equation above,

18 g of H2O reacted to produce 74 g of Ca(OH)2.

Therefore, 10 g of H2O will react to produce = (10 × 74)/18 = 41.11 g of Ca(OH)2.

Therefore, 41.11 g of Ca(OH)2 were obtained from the reaction.

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