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4 years ago

Under the doppler effect, if the source of a wave is moving, it must be changing the frequency of the wave. true false

Physics

1 answer:

Ede4ka [16]4 years ago

4 0

True, a source coming towards you has an increased frequency, a source moving away from you has a reduced frequency.

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*100 points, please do all if not most of the questions listed, thank you*

e-lub [12.9K]

Answer:

1a.5km

2a. 31536000 seconds

2b.2800000 centimeters

2c.45,000,000 Milligrams

2d.0.0141667 m/s

2e.2.592 x 10^10 km/day

2f .8.23x10^-7m

2g.0.0000085 m3

Explanation:

1a.(25km/5)(1000m/1km)(1h/3600s) =(5km)( 1) (1) =5km

pls mark as brainliest

3 0

3 years ago

A truck heading east has an initial velocity of 6 m/s. It accelerates at 2 m/s2 for 12 seconds. What distance does the truck tra

omeli [17]

Vf = vi + at
vf = 6 + (2)(12)
vf = 6 + 24
vf = 30

2as = vf² - vi²
2(2)s = (30)² - (6)²
4s = 900 - 36
4s = 864
s = 864/4
s = 216
<span>d = 216</span>

6 0

3 years ago

Read 2 more answers

Which change to a circuit is most likely to decrease its electrical power?

Harlamova29_29 [7]

Answer:

It's D

Explanation:

8 0

3 years ago

Read 2 more answers

A mass of 790 kg is hanging from a crane (neglect the mass of the cable and the hook). While the mass is being lowered, it is sp

Margarita [4]

Answer:

Explanation:

Given

mass of object hanging from crane is $m=790\ kg$

mass is speeding up with $a=2.7\ m/s^2$

If T is the Tension in the cable then

$mg-T=ma$

$T=mg-ma$

$T=m(g-a)$

$T=790\times (9.8-2.7)$

$T=790\times 7.1$

$T=5609\ N$

8 0

4 years ago

A conductor shaped as a circular loop with a radius of 4.0 m is located in a uniform but changing magnetic field. If the maximum

bekas [8.4K]

Answer:

$\frac{\delta B}{\delta t}= 0.0995 \ T/s$

Explanation:

Given that :

The radius of the circular loop = 4.0 m

Maximum Emf $E_{max}$ = 5.0 V

The maximum rate at which the magnetic field strength is changing if the magnetic field is oriented perpendicular to the plane in which the loop lies can be determined via the expression;

$E_{max}$ = $Area (A) * \frac{\delta B}{\delta t}$

$E_{max}$ = $\pi r^2 * \frac{\delta B}{\delta t}$

5.0 = $\pi * (4.0)^2 * \frac{\delta B}{\delta t}$

5.0 = $50.27 * \frac{\delta B}{\delta t}$

$\frac{\delta B}{\delta t}= \frac{5}{50.27}$

$\frac{\delta B}{\delta t}= 0.0995 \ T/s$

5 0

3 years ago