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kaheart [24]
1 year ago
11

An earthmover slows from 42.0 km/h to 4.00 km/h in 4.75 s. What is its rate of acceleration in m/s2

Physics
1 answer:
Simora [160]1 year ago
6 0

acceleration (a) = change in velocity / change in time

Δv = final velocity - initial velocity = 4 km/h - 42 km/h = -38 km/h

Δt = 4.75 s

convert km/h to m/s

-38/ 3.6 = -10.56 m/s

a = -10.56 m/s / 4.75 s = -2.23 m/s^2

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a=2.9\ m/sec^2

Explanation:

<u>Net Forces and Acceleration</u>

The second Newton's Law relates the net force F_r acting on an object of mass m with the acceleration a it gets. Both the net force and the acceleration are vector and have the same direction because they are proportional to each other.

\vec F_r=m\vec a

According to the information given in the question, two forces are acting on the swimming student: One of 256 N pointing to the south and other to the west of 104 N. Since those forces are not aligned, we must add them like vectors as shown in the figure below.

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