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kaheart [24]
1 year ago
11

An earthmover slows from 42.0 km/h to 4.00 km/h in 4.75 s. What is its rate of acceleration in m/s2

Physics
1 answer:
Simora [160]1 year ago
6 0

acceleration (a) = change in velocity / change in time

Δv = final velocity - initial velocity = 4 km/h - 42 km/h = -38 km/h

Δt = 4.75 s

convert km/h to m/s

-38/ 3.6 = -10.56 m/s

a = -10.56 m/s / 4.75 s = -2.23 m/s^2

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Answer:

Explanation:

Velocity is at its greatest when kinetic energy is at its max which is when all the ball's energy has been transformed from potential energy to kinetic energy which is at the lowest point in its travels (assuming the ball is rolling down a ramp). You have no picture here so this answer is a general one, not a specific one.

8 0
3 years ago
g A lighter ball A with momentum PA=5.0 kg∙m/s in positive x-direction approaches a heavier ball B at rest before the collision.
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Answer:

7kgm/s

Explanation:

Using the law of conservation of momentum which states that the sum of momentum of bodies before collision is equal to the sum of the bodies after collision.

Let P1A and P1B be the initial momentum of the bodies A and B respectively

Let P2A and P2B be the final momentum of the bodies A and B respectively after collision.

Based on the law:

P1A+P2A = P1B + P2B

Given P1A = 5kgm/s

P2A = 0kgm/s(ball B at rest before collision)

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3 years ago
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3 0
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bogdanovich [222]
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3 years ago
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Explanation:

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