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2 years ago

What constant acceleration is required to increase the speed of a car from 26 mi/h to 51 mi/h in 5 seconds

Physics

1 answer:

mr_godi [17]2 years ago

8 0

2.25 m/s² of acceleration is required to increase the speed of a car from 26 mi/h to 51 mi/h in 5 seconds.

To find the answer, we need to know about the acceleration.

<h3>What is acceleration?</h3>

Acceleration is given as the ratio of velocity to time.
Mathematically, acceleration= velocity/time.

<h3>What is the acceleration required to increase the speed of a car from 26 mi/h to 51 mi/h in 5 seconds?</h3>

Here change in velocity of the car is 51-26= 25 mi/h.
As 1 mi/h = 0.45 m/s. So 25mi/h = 11.25 m/s.
Acceleration= (11.25m/s)/5s = 2.25 m/s².

Thus, we can conclude that the constant acceleration is 2.25 m/s².

Learn more about the acceleration here:

brainly.com/question/460763

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This is the step by step explanation to the above question:

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3 years ago

A photon of red light (wavelength = 710 nm) and a ping-pong ball (mass = 2. 40 × 10^-3 kg) have the same momentum. At what speed

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The speed of the ball moving is

$v = 3.94 \times 10 {}^{ - 25}m/s$

what is momentum?

The momentum p of a classical object of mass m and velocity v is given by pclassical =mv.

For photons with wavelength λ,this equation does not hold.Instead, the momentum of the Photon is given by p Photon = h/λ

where,h is the planck's constant.

The momentum of the red Photon is

given:

$h = 6.626 \times 10 {}^{ - 34}kgm {}^{2}/s(plancks \: constant)$

$λ = 700 \times 10 {}^{ - 9} m(photons \: wavelength)$

$p \: photons = \frac{6.626 \times 10 {}^{ - 34}kgm {} ^{2}/s }{700 \times 10 {}^{ - 9}m }$

$= 9.47 \times 10 {}^{ - 28}kgm /s$

since,the Photon and the ping-pong ball have the same momentum,we have

$pball = pphotons = \frac{6.626 \times 10 {}^{ - 34}kgm/s }{700 \times 10 {}^{ - 9} }$

$pball = mv,m = 2.40 \times 10 {}^{ - 3}kg$

$v = 3.94 \times 10 {}^{ - 25} m/s$

Therefore, if the red photon and the ping-pong ball have the same momentum, the ping-pong ball must have a speed of approximately

$v = 3.94 \times 10 {}^{ - 25}m/s$

learn more about momentum of photon from here: brainly.com/question/28197406

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