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Lostsunrise [7]
3 years ago
12

What occurs during interphase? (Select all that apply.)

Chemistry
2 answers:
murzikaleks [220]3 years ago
6 0

Answer:

during interphase the cells start to grow

DochEvi [55]3 years ago
6 0

cells grow, store up energy, and take in nutrients

hope it helped :)

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Carmen has a sample of matter. It is clear and smells sour. The sample is also thick but it flows when poured. Which is the best
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liquid

Explanation:

In the given context, the sample as collected by Carmen is clear  and the sample has a sour smell. It is also mentioned that the sample is thick sample and when the sample is poured on a surface it begins to flow.

Such a sample would be a liquid sample because anything that flows is a liquid. The liquid sample has a high viscosity since it is thick.

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What is the theoretical yield of aluminum that can be produced by the reaction of 60.0 g of aluminum oxide with 30.0 g of carbon
Varvara68 [4.7K]

Answer: 31.8 g

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} Al_2O_3=\frac{60.0g}{102g/mol}=0.59moles

\text{Moles of} C=\frac{30.0g}{12g/mol}=2.5moles

Al_2O_3+3C\rightarrow 2Al+3CO  

According to stoichiometry :

1 mole of Al_2O_3 require 3 moles of C

Thus 0.59 moles of Al_2O_3 will require=\frac{3}{1}\times 0.59=1.77moles  of C

Thus Al_2O_3 is the limiting reagent as it limits the formation of product and C is the excess reagent as it is present in more amount than required.

As 1 mole of Al_2O_3 give = 2 moles of Al

Thus 0.59 moles of Al_2O_3 give =\frac{2}{1}\times 0.59=1.18moles  of Al

Mass of Al=moles\times {\text {Molar mass}}=1.18moles\times 27g/mol=31.8g

Thus 31.8 g of Al will be produced from the given masses of both reactants.

5 0
3 years ago
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