Answer:
Cyclic butanol , 1 cyclopropyl methanol, 1-methyl cyclo propan-1-ol.
Explanation:
IR wave-number of O-H bond = 
The intensity of the signal is broad and strong.
IR wave number of C=C bond = 
The intensity of the signal is weak.But for the given chemical formula it didn't show any signal in its IR spectrum.This means that no unsaturation is present.
IR wave number of C=O bond = 
The intensity of the signal is broad and strong.But for the given chemical formula it didn't show any signal in its IR spectrum. This means that no C=O is present in the compound
For the given formula the possible structures wil be:

As we know from the I.R. data that no unsaturation is present which indicates that the given compound has cyclic structure.
The possible structures are attached in an image.
Answer:
iron
Explanation:
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The missing part of the question is shown in the image attached
Answer:
C10H22(l) + 31/2 O2 (g)-----> 10CO2(g) + 11H2O(l)
V= 70.4L of CO2
Explanation:
Equation of the reaction is:
C10H22(l) + 31/2 O2 (g)-----> 10CO2(g) + 11H2O(l)
Number of moles of decane = mass/ molar mass
Molar mass of decane= 122gmol-1
n= 0.370×10^3g/122gmol-1= 3.0 moles
T= 13°C +273=286K
P= 1atm
R= 0.082 atmLK-1mol-1
From :
PV= nRT
V= nRT/P
V= 3.0×0.082×286/1
V= 70.4L of CO2
Answer:
Mass percent of Mn is 34.76 %
Explanation:
<em>Mass percent</em> of an element is the mass of that element divided by the total mass of the elements forming that compound (or molecular mass.
So,
Mass percent of Mn will be given as,
%Mn = Atomic Mass of Mn / Molecular Mass of KMnO₄ × 100
So,
Atomic Mass of Mn = 54.94 g/mol
Molecular Mass of KMnO4 = 158.034 g/mol
Putting values in above formula,
%Mn = 54.94 g/mol ÷ 158.034 g/mol × 100
%Mn = 34.76 %
The radius of a chlorine ion is larger than the radius of a chlorine atom because the effective nuclear charge decreases, therefore the inward force decreases, increasing the ionic radius.