Its work ability should be what you need<span />
Answer:
See explanation
Explanation:
The reaction occurs as follows;
KBr(aq) + AgNO3(aq) ----> AgBr(s) + KNO3(aq)
Number of moles of AgBr formed = mass /molar mass =1.740 g/187.77 g/mol = 0.0093 moles
From the reaction equation;
1 mole of KBr yields 1 mole of AgBr
Hence the number of moles of KBr reacted = 0.0093 moles
Mass of KBr present = 0.0093 moles × 119g/mol = 1.11 g
Mass of KNO3 = 2.850 g - 1.11 g = 1.74 g
Percentage of KBr = 1.11 g/2.850 g × 100 = 38.9%
Percentage of KNO3 = 1.74 g/2.850 g × 100 = 61.1%
Answer:
Because of statements (a), (c) and (d).
Explanation:
Let's evaluate each statement to know why they focus on higher alcohols instead of ethanol:
(a) It is easier to produce higher alcohols in microbes than it is to produce ethanol<u>.</u> This is true<u> since ethanol is the major biofuel in the world because it can be easily produced by fermentation technology developed a long time ago. Recently, higher alcohols are produced from microorganisms that are used as microbial cell factories.</u>
(b) Higher alcohols have a higher hygroscopicity than ethanol. This is false since ethanol is more hygroscopic than higher alcohols.
(c) Higher alcohols have a lower vapor pressure than ethanol. This is true, ethanol has a higher vapor pressure than higher alcohols. The vapor pressure is important since it can affect the proper cold starting of the engine.
(d) Higher alcohols have a higher energy density than ethanol. This is true since the production of higher alcohols as biofuels is more desirable than the ethanol because higher alcohols have a high energy density and other more advantages than the use of ethanol.
Therefore the answer of why did they focus on higher alcohols to add to or substitute gasoline instead of ethanol is because of the statements (a), (c) and (d).
I hope it helps you!
Answer:
The concentration of the magnesium fluoride solution is 0.0020 M
Explanation:
Step 1: Data given
Mass of MgF2 = 0.031 grams
volume = 250 mL = 0.250 L
Molar mass of MgF2 = 62.3 g/mol
Step 2: Calculate moles
Moles MgF2 = mass MgF2 / molar mass MgF2
Moles MgF2 = 0.031 grams / 62.3 g/mol
Moles MgF2 = 4.98 *10^-4 moles
Step 3: Calculate concentration of MgF2
Concentration MgF2 = moles MgF2 / volume
Concentration MgF2 = 4.98 *10^-4 / 0.250 L
Concentration = 0.0020 M
The concentration of the magnesium fluoride solution is 0.0020 M