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svet-max [94.6K]
3 years ago
7

If a parent cell has 23 chromosomes and reproduces asexually through mitosis,how many chromosomes will each of its daughter cell

s have?
Chemistry
1 answer:
Fittoniya [83]3 years ago
5 0

Answer:

Im pretty sure it would be 23

Explanation:

If it divide asexually it would be identical

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How many electrons are there in the valence shell of the oxygen atom of water? O a. 2 O 6.4 OC.6 O d. 8
denpristay [2]

Answer:

d. 8

Explanation:

Valence electrons of oxygen = 6

Valence electrons of hydrogen = 1  

The total number of the valence electrons  = 6 + 2(1) = 8

The Lewis structure is drawn in such a way that the octet of each atom and duet for the hydrogen in the molecule is complete.

In the water molecule,

<u>Oxygen has 2 bond pairs and two lone pairs which means that the total electrons in the valence shell is 8.</u>

7 0
3 years ago
Suppose the thermometer is miscalibrated to read .3c higher than actual. does this error in calibrations result in the molar mas
andrey2020 [161]
The answer to this question would be: too low

Molar mass would be determined by the number of mol and the mass of the object. Mass wouldn't be influenced by the temperature, but number of mol is. Using ideal gas formula of PV=nRT you can conlude that the amount of mol(n) is inversely related to the temperature (T).
If the temperature is higher than it supposed to be, then the amount of mol would be lower than it supposed to be. 
5 0
3 years ago
Propane has a normal boiling point of -42.04 °C and a heat of vaporization of 24.54 kJ/mole. What is the vapor pressure of propa
Mademuasel [1]

Answer : The vapor pressure of propane at 25.0^oC is 17.73 atm.

Explanation :

The Clausius- Clapeyron equation is :

\ln (\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}\times (\frac{1}{T_1}-\frac{1}{T_2})

where,

P_1 = vapor pressure of propane at 25.0^oC = ?

P_2 = vapor pressure of propane at normal boiling point = 1 atm

T_1 = temperature of propane = 25.0^oC=273+25.0=298.0K

T_2 = normal boiling point of propane = -42.04^oC=230.96K

\Delta H_{vap} = heat of vaporization = 24.54 kJ/mole = 24540 J/mole

R = universal constant = 8.314 J/K.mole

Now put all the given values in the above formula, we get:

\ln (\frac{1atm}{P_1})=\frac{24540J/mole}{8.314J/K.mole}\times (\frac{1}{298.0K}-\frac{1}{230.96K})

P_1=17.73atm

Hence, the vapor pressure of propane at 25.0^oC is 17.73 atm.

3 0
3 years ago
Plutonium-240 decays according to the function \[Q(t)=Q _{o}e ^{-kt}\] where Q represents the quantity remaining after t years a
marishachu [46]
To answer the question above, substitute the given values to the given equation,
                                   Q(t) = Q x e^-kt
  
                          12 grams = (36 grams) x e^(-0.00011)(t)

Solving for t gives t = 9,987.38 years or approximately equal to 9,990 years. Thus, the answer is letter C.












4 0
3 years ago
Read 2 more answers
What is molarity of 47.0 g KCl dissolved in enough water to give 375 mL of solution?
natita [175]

This question provides us –

  • Weight of \bf  KCl is = 47 g
  • Volume, V = 375 mL

__________________________________________

  • Molar Mass of \bf   KCl –

\qquad \twoheadrightarrow\bf  39.0983 \times 35.453

\qquad \twoheadrightarrow\bf 74.5513

<u>Using formula</u> –

\qquad \purple{\twoheadrightarrow\bf Molarity _{(Solution)} =  \dfrac{ W\times 1000}{MV}}

\qquad \twoheadrightarrow\bf Molarity _{(Solution)}  = \dfrac{ 47 \times 1000}{74.5513\times 375}

\qquad \twoheadrightarrow\bf Molarity _{(Solution)}  = \dfrac{47000}{27956.7375}

\qquad \twoheadrightarrow\bf Molarity _{(Solution)}  = \cancel{\dfrac{47000}{27956.7375}}

\qquad \twoheadrightarrow\bf Molarity _{(Solution)}  = 1.68117M

\qquad \pink{\twoheadrightarrow\bf Molarity _{(Solution)}  = 1.7M}

  • Henceforth, Molarity of the solution is = 1.7M

___________________________________________

6 0
2 years ago
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