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kondaur [170]
3 years ago
12

Select all that apply. Which of the following are true statements?.

Chemistry
2 answers:
Nimfa-mama [501]3 years ago
6 0
I believe A,C, and D are correct
olga55 [171]3 years ago
4 0

Explanation:

Charges which are alike or similar are repulsive in nature or we can say that like charges repel each other.

Whereas opposite or unlike charges attract each other.

On the other hand, when a charged object is brought in contact with a neutral object then the neutral object acquires an opposite charge which reads to attraction between both the objects. This process of inducing the charge is known as induction.

Thus, we can conclude that the following statements are true.

  • Like charges repel.
  • Unlike charges attract.
  • Charged objects attract neutral objects due to induction.
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A 5.00g of X, the product of organic synthesis is obtained in a 1.0 dm3 aqueous solution. Calculate the mass of X that can be ex
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mass of X extracted from the aqueous solution by 50 cm³ of ethoxy ethane = 3.33 g

Explanation:

The partition coefficient of X between ethoxy ethane (ether) and water, K is given by the formula

K = concentration of X in ether/concentration of X in water

Partition coefficient, K(X) between ethoxy ethane and water = 40

Concentration of X in ether = mass(g)/volume(dm³)

Mass of X in ether = m g

Volume of ether = 50/1000 dm³ = 0.05 dm³

Concentration of X in ether = (m/0.05) g/dm³

Concentration of X in water = mass(g)/volume(dm³)

Mass of X in water left after extraction with ether = (5 - m) g

Volume of water = 1 dm³

Concentration of X in water = (5 - m/1) g/dm³

Using K = concentration of X in ether/concentration of X in water;

40 = (m/0.05)/(5 - m)

(m/0.05) = 40 × (5 - m)

(m/0.05) = 200 - 40m

m = 0.05 × (200 - 40m)

m = 10 - 2m

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Therefore, mass of X extracted from the aqueous solution by 50 cm³ of ethoxy ethane = 3.33 g

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