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3 years ago

Select all that apply. Which of the following are true statements?.

Chemistry

2 answers:

Nimfa-mama [501]3 years ago

6 0

I believe A,C, and D are correct

olga55 [171]3 years ago

4 0

Explanation:

Charges which are alike or similar are repulsive in nature or we can say that like charges repel each other.

Whereas opposite or unlike charges attract each other.

On the other hand, when a charged object is brought in contact with a neutral object then the neutral object acquires an opposite charge which reads to attraction between both the objects. This process of inducing the charge is known as induction.

Thus, we can conclude that the following statements are true.

Like charges repel.

Unlike charges attract.

Charged objects attract neutral objects due to induction.

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A 151.5-g sample of a metal at 75.0°C is added to 151.5 g at 15.1°C. The temperature of the water rises to 18.7°C. Calculate the

Kryger [21]

Answer:

The specific heat capacity of the metal is 0.268 J/g°C

Explanation:

Step 1: Data given

Mass of the metal = 151.5 grams

The temperature of the metal = 75.0 °C

Temperature of water = 15.1 °C

The temperature of the water rises to 18.7°C.

The specific heat capacity of water is 4.18 J/°C*g

Step 2: Calculate the specific heat capacity of the metal

heat lost = heat gained

Q = m*c*ΔT

Qmetal = - Qwater

m(metal) * c(metal) * ΔT(metal) = m(water) * c(water) * ΔT(water)

⇒ mass of the metal = 151.5 grams

⇒ c(metal) = TO BE DETERMINED

⇒ΔT( metal) = T2 - T1 = 18.7 °C - 75.0 °C = -56.3 °C

⇒ mass of the water = 151.5 grams

⇒ c(water) = 4.184 J/g°C

⇒ ΔT(water) = 18.7° - 15.1 = 3.6 °C

151.5g * c(metal) * -56.3°C = 151.5g * 4.184 J/g°C * 3.6 °C

c(metal) = 0.268 J/g°C

The specific heat capacity of the metal is 0.268 J/g°C

5 0

4 years ago

For the reaction CO2(g) + H2(g)CO(g) + H20(g)

Studentka2010 [4]

Answer:

The ΔG° is 29 kJ and the reaction is favored towards reactant.

Explanation:

Based on the given information, the ΔH°rxn or enthalpy change is 41.2 kJ, the ΔS°rxn or change in entropy is 42.1 J/K or 42.1 * 10⁻³ kJ/K. The temperature given is 289 K. Now the Gibbs Free energy change can be calculated by using the formula,

ΔG° = ΔH°rxn - TΔS°rxn

= 41.2 kJ - 289 K × 42.1 × 10⁻³ kJ/K

= 41.2 kJ - 12.2 kJ

= 29 kJ

As ΔG° of the reaction is positive, therefore, the reaction is favored towards reactant.

5 0

3 years ago

Is it fair that some scientists have received more credit than others for their work on the development of the periodic table? W

Gre4nikov [31]

Yes because some work harder than others to get their credit for developing the periodic table

6 0

3 years ago

Which is NOT a way nitrogen can be fixed or made more useful?

stich3 [128]

This doesn’t have a multiple choice part to answer.

7 0

3 years ago

Does the amount of methanol increase, decrease, or remain the same when an equilibrium mixture of reactants and products is subj

denis23 [38]

Answer:

a. Methanol remains the same

b. Methanol decreases

c. Methanol increases

d. Methanol remains the same

e. Methanol increases

Explanation:

Methanol is produced by the reaction of carbon monoxide and hydrogen in the presence of a catalyst as follows; 2H2+CO→CH3OH.

a) The presence or absence of a catalyst makes no difference on the equilibrium position of the system hence the methanol remains constant.

b) The amount of methanol decreases because the equilibrium position shifts towards the left and more reactants are formed since the reaction is exothermic.

c) If the volume is decreased, there will be more methanol in the system because the equilibrium position will shift towards the right hand side.

d) Addition of helium gas has no effect on the equilibrium position since it does not participate in the reaction system.

e) if more CO is added the amount of methanol increases since the equilibrium position will shift towards the right hand side.

3 0

3 years ago