Answer:
Amount of excess Carbon (ii) oxide left over = 23.75 g
Explanation:
Equation of the reaction: Fe₂O₃ + 3CO ----> 2Fe + 3CO₂
Molar mass of Fe₂O₃ = 160 g/mol;
Molar mass of Carbon (ii) oxide = 28 g/mol
From the equation of reaction, 1 mole of Fe₂O₃ reacts with 3 moles of carbon (ii) oxide; i.e. 160 g of iron (iii) oxide reacts with 84 g (3 * 28 g) of carbon (ii) oxide
450 g of Fe₂O₃ will react with 450 * 84/180) g of carbon (ii) oxide = 236..25 g of carbon (ii) oxide
Therefore the excess reactant is carbon (ii) oxide.
Amount of excess Carbon (ii) oxide left over = 260 - 236.25
Amount of excess Carbon (ii) oxide left over = 23.75 g
Answer: Molecules of gas are usually far apart and can be compressed unlike molecules of liquids.
Explanation:
The molecules of gases are usually far apart, moving freely and randomly, occupying extra space in the containing vessel. Hence, when compressed to become closely packed, gases have lower volume.
However, unlike gases, the molecules of a liquid are restricted, move less freely and occupy no extra space. Hence, liquids cannot be compressed, and their volume remains the same in their containing vessel.
Answer:
with what you didnt put a question, math equation or a attachment
