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Marrrta [24]
3 years ago
10

15 POINTS ASAP PLEASE!!

Chemistry
1 answer:
german3 years ago
8 0
Lymph<span> contains a variety of substances, including proteins, salts, glucose, fats, water, and white blood cells.</span>
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According to molecular orbital theory,  regions of  wave function with highest probability of finding electrons are areas with constructive interference.

An electron is a negatively charged subatomic particle that can exist either free or bound to an atom (not bound). A bound electron is one of the three primary types of particles that make up an atom, along with protons and neutrons. Protons, neutrons, and electrons combined make up the atom's nucleus. A proton's positive charge balances an electron's negative charge. When an atom has an equal number of protons and electrons, it is said to be in a neutral state. Electrons are distinct from other particles in a number of ways. They have a much lower mass, are found outside the nucleus, and exhibit both wave- and particle-like characteristics. The electron is a basic particle.

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Question :What's oxidation?<br>​
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How is gas different from a liquid
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What is the molarity of a 1.44 (m/v)% solution of an HCOOOH (Formic acid)?
AlexFokin [52]

This problem is providing the mass-volume percent of a formic acid solution so its molarity is required and found to be 0.313 M after the following calculations.

<h3>Molarity</h3>

In chemistry, units of concentration provide a measurable understanding of the relationship between the relative amounts of both solute and solvent. In the case of molarity, one must relate moles of solute and liters of solution as follows:

M=\frac{mol\ solute}{Volume\ solution \ in \ L}

In such a way, when given this mass-volume percent of 1.44% for the formic acid in the solution, one can assume there is 100 mL of solution and 1.44 g of solute (formic acid), which means one must convert the volume to liters and the mass to moles with:

mol\ solute=\frac{1.44g}{46.03g/mol} =0.0313mol\\\\Volume\ in \liters: 100mL*\frac{1L}{1000mL}=0.100L

Finally, we plug in these numbers in the equation for the calculation of molarity:

M=\frac{0.0313mol}{0.100L}\\\\M=0.313M

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2 years ago
What experiments did Lavoisier do?
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He did experiments with combustion and gas's
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