
The slope perpendicular to 1/4 or .25 is 4.
Then you would use point slope form to write the equation.
Then you could simiplify the equation to y=4x+32.
Answer: They are parallel
Step-by-step explanation:
If two lines are parallel , then they must have the same slope and if two lines are perpendicular , the product of their slope must be -1.
To check this , we must calculate the slope of the two lines given.
Slope = 
from the first point
= 2
= 1
= 5
= -1
substituting the values
slope 1 = 1 - 2 / -3 - 5
slope1 = -1 / -8
slope 1 = 1/8
Using the same format to calculate the slope of the second line
= -2
= 0
= -1
= 15
slope 2 = 0 - (-2) / 15 - (-1)
slope 2 = 2/16
slope 2 = 1/8
Since slope 1 = slope 2 , this implies that the lines are parallel
Answer:
The absolute value graph below does not flip.
Step-by-step explanation:
New graphs are made when transformed from their parents graphs. The parent graph for an absolute value graph is f(x) = |x|.
The equation used for a new graph transformed from the parent graph is in the form f(x) = a |k(x - d)| + c.
"a" shows vertical stretch (a>1) or vertical compression (0<a<1), and <u>flip across the x-axis if "a" is negative</u>.
"k" shows horizontal stretch (0<k<1) or horizontal compression (k>1), and <u>flip across the y-axis if "k" is negative</u>.
"d" shows horizontal shifts left (positive number) or right (negative number).
"c" shows vertical shifts up (positive) or down (negative).
The function f(x)=2|x-9|+3 has these transformations from the parent graph:
a = 2; Vertical stretch by a factor of 2
k = 1; No change
d = 9; Horizontal shift right 9 units
c = 3; Vertical shift up 3 units
Since neither "a" nor "k" was negative, there were no flips, <u>also known as reflections</u>.
HERE IS YOUR ANSWER
<span>114 = (1/3)p - 3
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Given tangent, ZN, to the circle and the arc
= 280°, we have that
the angle formed by the chord BZ and the tangent ZN, ∠BZN is 50°
<h3>Which method can be used to find ∠BZN?</h3>
The given parameters are;
A tangent to the circle O = ZN

Required:
Angle ∠BZN
Solution;
Please find attached the drawing of the circle and tangent
From the drawing, we have;
∠BOZ = 360° - 280° = 80°
ΔBOZ is an isosceles triangle, which gives;
∠BZO = ∠ZBO

∠OZN = 90° (by definition of a tangent)
∠OZN = ∠BZO + ∠BZN
∠BZN = ∠OZN - ∠BZO
Which gives;
∠BZN = 90° - 40° = 50°
- The measure of angle ∠BZN =<u> 50°</u>
Learn more about tangents to a circle here:
brainly.com/question/14561226