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2 years ago

Please help see attached file

Mathematics

1 answer:

____ [38]2 years ago

4 0

Answer:

Package A: 492in^2

Package B: 404in^2

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A phone company charges for service according to the formula: C ( n ) = 29 + 0.04 n , where n is the number of minutes talked, a

melisa1 [442]

Hello!

<h2>Answer: </h2>

Slope = 0.004

Vertical Intercept = 29.

<h2>Explanation:</h2>

Basically, you can rearrange this equation so that is in the form of y = mx + b.

y = mx + b

C(n) = 0.04n + 29

The slope represents the rate of change of the cost per minute talked, and the 29 (vertical intercept) represents the monthly fee. The monthly fee will stay the same, however, the number of minutes talked is susceptible to change, hence the variable <em>n </em>represents it.

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2 years ago

Find P(1), if p(x)=(x-1) (x+1)

Mkey [24]

Answer:

Step-by-step explanation:

So we have the function:

$p(x)=(x-1)(x+1)$

To find p(1), substitute x for 1:

$p(1)=((1)-1)((1)+1)\\$

Simplify:

$p(1)=(0)(2)\\p(1)=0$

Thus, p(1) is 0.

8 0

3 years ago

Read 2 more answers

A rhombus has diagonals 500 yd and 800 yd in length. Find the area in square miles.

nordsb [41]

We know that
<span>A simple formula for the area of a rhombus when you know the lengths of the diagonals is half the product of the diagonals
</span>
Area=d1*d2/2
d1=500 yd
d2=800 yd

1 mile is equal to -----> 1760 yd
x mile---------------> 500 yd
x=500/1760----> x=0.2841 mi

1 mile is equal to -----> 1760 yd
x mile---------------> 800 yd
x=800/1760----> x=0.4545 mi

Area=(0.2641*0.4545)/2-----> 0.06 miles²

the answer is
0.06 miles²

8 0

2 years ago

Two functions are shown below.

marusya05 [52]

Answer: (-3,20) (2,35)

Step-by-step explanation: well if the 2 is an exponent then this is the answer, I don’t know the step by step though sorry. <3

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2 years ago

A plane is flying at a heading of 125° at a speed of 320 mph. The wind is blowing from due North at a speed of 35 mph. Find the

ad-work [718]

Answer:

$301.29\ \text{mph}$

$119.5^{\circ}$

Step-by-step explanation:

$v_p$ = Velocity of plane = 320 mph

$v_w$ = Velocity of wind = 35 mph

$\theta$ = Angle between wind and plane directions = $125^{\circ}$

From triangle law we have resultant

$v_r=\sqrt{v_p^2+v_w^2+2v_pv_w\cos\theta}\\\Rightarrow v_r=\sqrt{320^2+35^2+2\times 320\times 35\cos125^{\circ}}\\\Rightarrow v_r=301.29\ \text{mph}$

Direction is given by

$\phi=\tan^{-1}\dfrac{v_p\sin\theta}{v_w+v_p\cos\theta}\\\Rightarrow \phi=\tan^{-1}\dfrac{320\sin125^{\circ}}{35+320\cos125^{\circ}}\\\Rightarrow \phi=-60.46^{\circ}=180-60.46=119.5^{\circ}$

The magnitude of the plane is $301.29\ \text{mph}$ moving at an angle of $119.5^{\circ}$ .

8 0

2 years ago