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Bond [772]
2 years ago
15

Part A is asking how long the bridge is and Part B is asking how expensive it would be if each foot it 1500

Mathematics
1 answer:
katrin [286]2 years ago
4 0

Answer:

(a)80 feet

(b)$120,000

Step-by-step explanation:

<u>Part A</u>

<u>Intersecting Secant-Tangent Theorem</u>

If a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.

In the attached diagram, the theorem applied is:

|AX|^2=|UX|*|TX|

Comparing with our diagram:

|AX|=30 feet

|UX|=10 feet

Length of the Bridge,L

Therefore:

30^2=10 X ($Length of the Bridge+10)

900=10(L+10)

L+10=900/10

L+10=90

L=90-10=80 feet

Length of the Bridge=80 feet

<u>Part B</u>

If each foot costs $1500

Cost of the bridge=$1500*80=$120,000

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Did the population of Town C increase by at least 100 percent from the year 2000 to the year 2010 ? The population of Town C in
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Yes, the population of Town C increased by at least 100 percent from the year 2000 to the year 2010

<u>Statement 1:</u> The population of Town C in 2000 was 2/3 of the population in 2005

This tells us the population change from 2000 to 2005 since we need to know the population change from 2000 to 2010, this statement is not sufficient.

<u>Statement 2: </u>The population of Town C increased by a greater number of people from 2005 to 2010 than it did from 2000 to 2005.

Since statement 2 provides no information about the population change from 2000 to 2005, there is no to answer this question with certainty. thus, statement 2 is not sufficient

<u>Statement 1 and Statement 2 combined:</u>

Let X= the population in 2000

Let Y= the population in 2005

Let Z= the population in 2010

From statement 1, we can write: X=\frac{2}{3}Y

Multiply both sides by 3 to get 3X=2Y

Divide both sides by 2 to get \frac{3}{2}X=Y

=>Y=1.5X

As per statement 2, let's first determine the increase in the number of people from 2000 to 2005

If Y=1.5X, we know

X= the population in 2000

1.5X= the population in 2005

1.5X-X=0.5X

So, the population increased  0.5X from 2000 to 2005

So,  from 2005 to 2010, the population increased at least 0.5X

1.5X= the population in 2005

1.5X+0.5X=2.0X

So, the population in 2010 was at least 2.0X

In other words, the population at least doubled from 2000 to 2010

So, the answer to the target question is yes, the population of Town C increased by at least 100 percent from the year 2000 to the year 2010

Did the population of Town C increase by at least 100 percent from the year 2000 to the year 2010?

(1) The population of Town C in 2000 was 2/3 of the population in 2005.

(2) The population of Town C increased by a greater number of people from 2005 to 2010 than it did from 2000 to 2005.

Learn more about population here brainly.com/question/16788694

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