The large triangle is an isosceles since both angles at the base each equal 42°.
In an isosceles triangle the altitude z is at the same time median , then it bisects the opposite side in the middle . So w = 120/2 = 60
Now let's calculate z:
tan 42° = (opposite side) / (adjacent side) = z/60
tan 42° = 0.9,
0.9 = z/60 and z = 54
In the right triangle ABC wherein AB is the hypotenuse, BC is the opposite and CA is the adjacent tanA=0.45. The approximate length of AB which is the hypotenuse is 22, Opposite (BC) is 9 and Adjacent (CA) is 20. You need to use pythagorean formula in getting the length of AB.
YOUR ANSWER IS (22).
Answer:
3.8
Step-by-step explanation:
We are going to plug in the values of the equation, so h(t)=-4.9^2+v0t+h0 will
now be h(t)=-4.9^2+0+70
Now we will find the a b and c of the equation, a=-4.9 b=0 c=70
Now we must find the discriminant of the equation, which the equation for that is D=b^2+(-4)(a)(c)
So D=1,372
Now we use the quadratic formula (see picture below for finished product)
11 is the biggest and the 22
Answer:
C. (x + 10)
Step-by-step explanation:
