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d1i1m1o1n [39]
3 years ago
8

Approximately how many times greater is 2.3 than 1.15 ?

Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
8 0
It is 2 times greater a s1.15 x 2=2.3
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I have the answer but I just want to make sure
ycow [4]

Answer:

C. (-11, -9)

Step-by-step explanation:

a-3b=16

a=b-2

(b-2)-3b=17

b-2-3b=16

-2b=18

-b=9

b=-9

a=b-2

a=-9-2

a=-11

C. (-11, -9)


4 0
4 years ago
Need help with this ASAP! thank you!
andreyandreev [35.5K]

Answer:

-4x^3 + 9x^2+35x -45

Step-by-step explanation:

The notation (f*g)(x) actually just means f(x)*g(x)

We just substitute what f(x) is and what g (x) is

(4x-9) * (-x^2 - 3x + 5 )

4x * -x^2 = -4x^3

4x * -3x = -12x

4x*5 = 20x

-4x^3 + -12x+20x

and

-9 * -x^2 = 9x^2

-9*-3x = 27x

-9*5 = -45

-4x^3 + -12x+20x + 9x^2 + 27x +-45

Now to put this in standard form, we have to order it with the terms with the highest exponents to the ones with the lowest exponents

-4x^3 + 9x^2 -12x+20x+27x -45

-12x+20x+27x

-12x+47x

35x

-4x^3 + 9x^2+35x -45

-45 goes last because it is equal to -45x^0

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