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d1i1m1o1n [39]
3 years ago
8

Approximately how many times greater is 2.3 than 1.15 ?

Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
8 0
It is 2 times greater a s1.15 x 2=2.3
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Suppose that there are two types of tickets to a show:Advance and same-day. Advance tickets cost $35 and same day tickets cost $
sdas [7]

Answer:    30 $15 tickets and 20 $35 tickets

Step-by-step explanation:

.X%2BY=50

2.15X%2B35Y=1150

From eq. 1,

15X%2B15Y=750

Subtract from eq. 2,

15X%2B35Y-15X-15Y=1150-750

20Y=400

Y=20

Then,

X%2B20=50

X=30

30 $15 tickets and 20 $35 ticket

Hope it helps

5 0
3 years ago
Given that there are 28.3495 grams in an ounce, find the number of ounces in the heaviest item listed above.
weeeeeb [17]

The answer is actually C. 87.79 oz


3 0
4 years ago
What is the nth term of the sequence? 4, 2, 0, –2, ..
tatuchka [14]

' n '    the 'n'th term

1               4
2               2 
3               0
4              -2 .

In general, the 'n'th term of the sequence is   A(n) = 6 - 2n  .
3 0
3 years ago
What is the formula for a confidence interval?
ikadub [295]

Answer:

a) The formula is given by mean \pm the margin of error. Where the margin of error is the product between the critical value from the normal standard distribution at the confidence level selected and the standard deviation for the sample mean.

b) \bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

If the distribution for X is normal or if the sample size is large enough we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

Part a

The formula is given by mean \pm the margin of error. Where the margin of error is the product between the critical value from the normal standard distribution at the confidence level selected and the standard deviation for the sample mean.

Part b

The confidence interval for the mean is given by the following formula:  

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

5 0
3 years ago
Help me out !!!!! Please
Stella [2.4K]
4x-t-4 is the final answer.
4 0
3 years ago
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