Answer:
(a) S = 1.8m
(b) F = 23.9N
Explanation:
The solution to this problem requires the knowledge of the concepts of constant acceleration motion for part (a) and newton's second law for part(b).
(a) s =(u + v)/2 ×t
(b) F = m(v-u)/t
u = 0m/s because the pitcher starts to throw the ball from rest
See attachment below for full solution steps.
The masses of both objects and the distance between their centers.
I feel that they should be regulated, mostly because its not safe for your ears to listen to such loud music. For example, if you were in the front of the concert you are more likely to get damage of your hearing more then the people in the back who have a slight chance.
Now, our ears can only handle up to 85 dB, thats why when you shoot a gun in a shooting range (if you've been at one) you wear hearplugs to protect you from the roughly 140-dB it gives off when fired. At rock concerts roughly 120-dB only 35-dB higher then what we are able to handle. The limit should be at most 90 dB because it is not too high and wont give us full on hearing damage to us in the future.
Answer:
Explanation:
As we know that the resistance of the wire is given as
now we know that both the bulbs are getting 12.5 A current in their branches
so total current in the circuit is given as
so we have total voltage across the wire is given as
now the load voltage is given as
Answer: 1,224.6km
S=r*theta
r=d/2=1.30m/2=.650m
Theta=(2pi/rev)rev
Theta=300,000rev(2pi/rev)=1,884,000rads
S=0.650m*1,844,000rad=1,224,600m
S=1,224,600m(1km/1000m)=1,224.6km
