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andre [41]
2 years ago
8

Peter, a 100 kg basketball player, lands on his feet after completing a slam dunk and then immediately jump up again to celebrat

e his basket. When his feet first touch the floor after the dunk,
his velocity is 5 m/s downward; when his feet leave the floor 0.50 s later, as he jumps back up,
his velocity is 4 m/s upward. What is the average reaction force exerted upward by the floor on Peter during this 0.50 s?
Physics
1 answer:
Ludmilka [50]2 years ago
6 0

Answer:

1800 N

Solution:

Impulse = mΔv = m * (u - v) .

 here m = 100 kg

          u = 4 m/s

          v = -5 m/s

  impulse = 100 x ( 4 - ( -5 ) ) = 900 Kg m/s .

Average reaction Force ( Favg ) = impulse / Δt

Average reaction Force ( Favg )  = 900kg·m/s / 0.5s

Average reaction Force ( Favg )  = 1800 N

You might be interested in
*please refer to photo* An electric field of magnitude 5.25 ✕ 10^5N/C points due south at a certain location. Find the magnitude
kvv77 [185]

Answer:

Approximately 3.86\; {\rm N} (given that the magnitude of this charge is -7.35\; {\rm \mu C}.)

Explanation:

If a charge of magnitude q is placed in an electric field of magnitude E, the magnitude of the electrostatic force on that charge would be F = E\, q.

The magnitude of this charge is q = 7.35\; {\rm \mu C}. Apply the unit conversion 1\; {\rm \mu C} = 10^{-6}\; {\rm C}:

\begin{aligned} q &= 7.35\; {\mu C} \times \frac{10^{-6}\; {\rm C}}{1\; {\mu C}} = 7.35\times 10^{-6}\; {\rm C}\end{aligned}.

An electric field of magnitude E = 5.25\times 10^{5}\; {\rm N \cdot C^{-1}} would exert on this charge a force with a magnitude of:

\begin{aligned}F &= E\, q \\ &= 5.25 \times 10^{5}\; {\rm N \cdot C^{-1}} \times (-7.35\times 10^{-6}\; {\rm C}) \\ &\approx 3.86\; {\rm N}\end{aligned}.

Note that the electric charge in this question is negative. Hence, electrostatic force on this charge would be opposite in direction to the the electric field. Since the electric field points due south, the electrostatic force on this charge would point due north.

4 0
2 years ago
1. A Zambeef delivery track travels 18 km north, 10 km east, and 16 km south. What is its final displacement from the origin?
VARVARA [1.3K]

Answer:

2km

Explanation:

Given data

We are told that the direction traveled are

North>>>East>>>South

Hence the displacement is defined as the distance away from the initial position is

Initial position =18km

FInal position = 16km

The displacement = 18-16= 2km

Hence the displacement is 2km

6 0
2 years ago
Concrete colums are constructed with reinforcing steel in them to make them stronger and more ductile. The reinforcing bars are
Sergio039 [100]

Answer:

21678.47223\ lbf-in^2

383.1109\ lbf-in^2

Explanation:

d = Diameter of column = 0.5 inch

A_c = Area of concrete = 119.4\ in^2

The strain in the system is conserved

\dfrac{F_sL}{A_sE_s}=\dfrac{F_cL}{A_cE_c}\\\Rightarrow F_c=\dfrac{F_sA_cE_c}{A_sE_s}\\\Rightarrow F_c=\dfrac{F_s \times 119.4\times 4.1\times 10^6}{8\times \dfrac{\pi \dfrac{1}{2^2}}{4}\times 29\times 10^6}\\\Rightarrow F_c=10.74658F_s

Now

F_c+F_s=50000\\\Rightarrow 10.74658F_s+F_s=50000\\\Rightarrow F_s=\dfrac{50000}{11.74658}\\\Rightarrow F_s=4256.55807\ lbf

F_c=10.74658F_s\\\Rightarrow F_c=10.74658\times 4256.55807\\\Rightarrow F_c=45743.44182\ lbf

Stress is given by

\sigma_s=\dfrac{4256.55807}{\pi \dfrac{1}{2^2}}{4}\\\Rightarrow \sigma_s=21678.47223\ lbf-in^2

The stress in the steel is 21678.47223\ lbf-in^2

\sigma_c=\dfrac{45743.44182}{119.4}\\\Rightarrow \sigma_s=383.1109\ lbf-in^2

The stress in the steel is 383.1109\ lbf-in^2

4 0
3 years ago
What provides the source of the earth’s magnetic field?
ololo11 [35]
<h2>Answer: the core of the earth</h2>

The explanation accepted by science until now, indicates that Earth's magnetic field is generated in the deepest of the terrestrial nucleus.

This is due to the movements of liquid metals in the core of the planet.

To explain it in more detail:

Right in the center of the Earth there is an internal core of solid iron at a very high temperature, this iron is as hot as the surface of the Sun, however, the pressure caused by the gravity force prevents it from becoming liquid. Around this inner core is the outer core, a layer of approximately 2000 km thick, composed of iron, nickel and small amounts of other metals in liquid state. Due to the lower pressure of the outer core, in relation to the inner core, the metal here is fluid (molten).

The differences in temperature, pressure and composition within the outer core cause convection currents in the molten metal, as the cold, dense matter sinks, and the warm, less dense matter rises. In addition, the Coriolis force, resulting from the spin of the Earth, also causes eddies in this mixture of molten metals.

This is how the movement of liquid iron inside the Earth generates electric currents, which in turn produce magnetic fields, and the spiral caused by the Coriolis force causes the magnetic fields to align in approximately the same direction, being this combined effect added to produce a vast magnetic field that envelops the entire planet.

This field extends from the terrestrial nucleus, progressively attenuating itself in outer space. However, it should be noted that unlike the field of a bar magnet, the Earth's magnetic field changes over time because it is actually generated by the movement of the iron alloys in the Earth's outer core, which causes the poles to move.

8 0
2 years ago
- An experienced pilot can keep an engineless glider aircraft aloft for hours by
Annette [7]

Answer:

F<em>lift=</em>5.00×10³ N

F<em>horizontal</em>=0.50×10³ N

F<em>g</em>=4.80×10³ N

Explanation:

A free-body diagram of the glider.

pretend this is a number line

^

|  F<em>lift</em>

|  

|

|---->F<em>horizontal</em>

|

| F<em>g</em>

|

∨

hope this helps! :)

6 0
2 years ago
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