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3 years ago

If 12 apples cost $10.20 how much does one apple cost?

Mathematics

2 answers:

trasher [3.6K]3 years ago

6 0

One apple costs 85 cents

marta [7]3 years ago

5 0

One apple costs $1.17
Hope this helps!!

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A car is travelling at exactly 6 miles per hour and accelerates at a constant rate to exactly 65 miles per hour.

vichka [17]

Answer:

$14878.04878miles/hours^2$

Step-by-step explanation:

Let's find a solution by understanding the following:

The acceleration rate is defined as the change of velocity within a time interval, which can be written as:

$A=(Vf-Vi)/T$ where:

A=acceleration rate

Vf=final velocity

Vi=initial velocity

T=time required for passing from Vi to Vf.

Using the problem's data we have:

Vf=65miles/hour

Vi=6miles/hour

T=14.8seconds

Using the acceleration rate equation we have:

$A=(65miles/hour - 6miles/hour)/14.8seconds$ , but look that velocities use 'hours' unit while 'T' uses 'seconds'.

So we need to transform 14.8seconds into Xhours, as follows:

$X=(14.8seconds)*(1hours/60minutes)*(1minute/60seconds)$

$X=0.0041hours$

Using X=0.0041hours in the previous equation instead of 14.8seconds we have:

$A=(65miles/hour - 6miles/hour)/0.0041hours$

$A=(61miles/hour)/0.0041hours$

$A=(61miles)/(hour*0.0041hours)$

$A=61miles/0.0041hours^2$

$A=14878.04878miles/hours^2$

In conclusion, the acceleration rate is $14878.04878miles/hours^2$

7 0

3 years ago

I give brinlilset sedrftgyhjkl;

mario62 [17]

Answer:

Its J

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

You bike 1 mile the first day of your training, 1.3 miles the second day, 1.9 miles the third day, and 3.1 miles the fourth d

JulsSmile [24]

Answer:

19.9 miles

Step-by-step explanation:

In this problem we have:

$d_1=1 mi$ is the distance travelled during the 1st day

$d_2=1.3 mi$ is the distance travelled during the 2nd day

$d_3=1.9 mi$ is the distance travelled during the 3rd day

$d_4=3.1 mi$ is the distance travelled during the 4th day

We notice that the difference between the distance travelled on the (n+1)-th day and the distance travelled on the n-th day doubles every day. In fact:

$d_2-d_1=0.3\\d_3-d_2=2\cdot 0.3 = 0.6\\d_4-d_3=2\cdot 0.6 = 1.2$

Which can be rewritten using the general formula:

$d_{n+1}-d_n=2(d_n-d_{n-1})$

This means that

$d_{n+1}=d_n+2(d_n-d_{n-1})$

By applying this formula recursively, we can find the 7th term, which is the distance travelled on the 7th day:

$d_1=1\\d_2=1.3\\d_3=1.9\\d_4=3.1\\d_5=3.1+2\cdot 1.2=5.5\\d_6=5.5+2\cdot 2.4=10.3\\d_7=10.3+2\cdot 4.8=19.9 mi$

So, the distance travelled on the 7th day is 19.9 miles.

7 0

3 years ago

For the following exercises, evaluate the function f at the values f(−2), f(−1), f(0), f(1), and f(2)

MatroZZZ [7]

Answer:

See below. I assume that (x) = 8x2 - 7x + 3 is really (x) = 8x^2 - 7x + 3

Step-by-step explanation:

Substitute the value of x given in f(x) into the equation f(x) = 8x^2 - 7x + 3

For example, f(0) would be f(0) = 8(0)^2 - 7(0) + 3. f(0) = 3

f(-2) would be f(-2) = 8(-2)^2 - 7(-2) + 3.

= 8*4 + 14 +3

= 32 + 17 therefore f(-2) = 49

x f(x)

-2 49

-1 18

0 3

1 4

2 21

4 0

2 years ago

Enrique is measuring the mass of a flower petal. Which unit of measurement should he use to eliminate the need to write the valu

GuDViN [60]

Answer:

do you have a pic of it.

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers