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vodomira [7]
2 years ago
5

With term describes the group of plants that most belong to?

Chemistry
1 answer:
Sergio039 [100]2 years ago
3 0

Answer:

It is called the Phylum Bryophyta.

Explanation:

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High concentrations of ammonia (NH3), nitrite ion, and nitrate ion in water can kill fish. Lethal concentrations of these specie
kykrilka [37]

Explanation:

It is known that molality is the number of moles present in kg of solution.

Mathematically,  Molality = \frac{\text{no. of moles of solute}}{\text{mass of solvent in Kg}}

The given data is as follows.

Molar mass of ammonia = 17 g/mol

Concentration = 1.002 mg/L = \frac{0.001002 g/L}{17 g/mol}

                        = 5.89 \times 10^{-4} mol/L

Also,    density = \frac{1 g}{mL} = 1 kg/L

Therefore, molality will be calculated as follows.

        Molality = \frac{5.89 \times 10^{-4} mol/L}{1 kg/L}

                      = 5.89 \times 10^{-4} mol/kg

And,

Molar mass of nitrite = 46 g/mol

Concentration = 0.387 mg/L = \frac{0.000412 g/L}{46 g/mol}

                        = 8.956 \times 10^{-6} mol/L

And, density = \frac{1 g}{mL} = 1 kg/L

Hence, molality = \frac{8.956 \times 10^{-6} mol/L}{1 kg/L}

                          = 8.956 \times 10^{-6} mol/kg  

Now, Molar mass of nitarte = 62 g/mol

      Concentration = 1352.2 mg/L

                              = \frac{1.3522 g/L}{62 g/mol}

                              = 0.02181 mol/L

Also, density = \frac{1 g}{mL} = 1 kg/L

Hence, molality will be calculated as follows.

         Molality = \frac{0.02181 mol/L}{1 kg/L}

                       = 0.02181 mol/kg

Therefore, molality of given species is 5.89 \times 10^{-4} mol/kg  for ammonia, 8.956 \times 10^{-6} mol/kg  for nitrite, and 0.02181 mol/kg for nitrate ion.

7 0
3 years ago
Tartaric acid, C4H6O6, has the first ionization constant with the value: Ka1 = 9.20 × 10-4. Calculate the value of pKb for the c
nirvana33 [79]

Answer:

pKb = 10.96

Explanation:

Tartaric acid is a dyprotic acid. It reacts to water like this:

H₂Tart  +  H₂O  ⇄  H₃O⁺   +  HTart⁻         Ka1

HTart⁻  +  H₂O  ⇄  H₃O⁺   +  Tart⁻²           Ka2

When we anaylse the base, we have

Tart⁻²   +  H₂O  ⇄  OH⁻  +  HTart⁻       Kb1

HTart⁻  +  H₂O  ⇄  OH⁻  +    H₂Tart          Kb2

Remember that Ka1 . Kb2  = Kw, plus pKa1 + pKb2 = 14

Kb2 = Kw / Ka1  →   1×10⁻¹⁴ / 9.20×10⁻⁴  = 1.08×10⁻¹¹

so pKb = - log Kb2   → - log 1.08×10⁻¹¹ = 10.96  

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3 years ago
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How does knowing the reactants and ______ help you classify a chemical reaction ?
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What does all flexible objects have in common
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3 years ago
Describe all the relationships between pressure, volume, and<br> temperature
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2 years ago
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