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Dimas [21]
3 years ago
11

How many moles of a gas would occupy 22.4 Liters at 273 K and 1 atm? Read bottom comment

Chemistry
1 answer:
Genrish500 [490]3 years ago
4 0

Answer:

The following relationship makes this possible: 1 mole of any gas at standard temperature and pressure (273 K and 1 atm) occupies a volume of 22.4 L.

Explanation:

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A 20-liter container contains 2. 0 moles of oxygen at a pressure of 92 kpa. The average kinetic energy of translation of oxygen
Elodia [21]

The average kinetic energy of translation of oxygen molecules in the gas is 5.05 × 10⁻²¹

The given data is

n = 2

v = 20

P = 92

K.E = 3 / 2 KbT

      = 3 / 2 PV / N

     = 3 / 2 Pv / nNa

K.E = 3 / 2 × 9 × 1.013 × 10⁵ × 20 × 10⁻³ / 2 × 6.022 × 10²³

K. E = 5.05 × 10⁻²¹ J

<h3>Average kinetic energy</h3>

The average kinetic energy (K) is equal to one half of the mass of each gas molecule times the RMS speed squared

Hence, the average kinetic energy is 5.05 × 10⁻²¹ J

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7 0
1 year ago
Liquid butane, C4H10, is stored in cylinders to be used
Ganezh [65]

Answer:

  • <u>13.0kJ</u>

Explanation:

The<em> heat</em> to <em>vaporize</em> a l<em>iquid</em> is equal to the amount of liquid in moles multiplied by the specific <em>heat of vaporiztion</em> per mole.

First, calculate the number of moles in 35.5g of <em>butane</em>.

  • Molar mass of butane: 58.124 g/mol

  • Number of moles = mass in grams/molar mass

  • Number of moles = 35.5g / 58.124g/mol = 0.6107632mol

Now, calculate the heat to vaporize that amount of <em>liquid butane</em>:

  • Heat = number of moles × specific heat of vaporization

  • Heat = 0.6107632mol × 21.3kJ/mol = 13.0 kJ

The answer must be reported with 3 significant figures.

3 0
4 years ago
Q4. The student started with 16.0 grams of NaCl, show the calculation for the percent error that
Vedmedyk [2.9K]

Answer:

72.6% Error

Explanation:

% error = \frac{Real-Measured}{Real} * 100

\frac{58.44-16}{58.44} *100= 72.6

58.44 is the weight of NaCl

5 0
3 years ago
A student obtains a mixture of the chlorides of two unknown metals, X and Z. The percent by mass of X and the percent by mass of
Aleksandr-060686 [28]

<u>Answer:</u> The additional information that is helpful in calculating the mole percent of XCl(s) and ZCl(s) is the molar masses of Z and X

<u>Explanation:</u>

To calculate the mole percent of a substance, we use the equation:

\text{Mole percent of a substance}=\frac{\text{Moles of a substance}}{\text{Total moles}}\times 100

Mass percent means that the mass of a substance is present in 100 grams of mixture

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

We require the molar masses of Z and X to calculate the mole percent of Z and X respectively

Hence, the additional information that is helpful in calculating the mole percent of XCl(s) and ZCl(s) is the molar masses of Z and X

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HELPPPPPP<br>Calculate the frequency of light with a wavelength 559nm​
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Answer:

Refer to the attachment

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3 years ago
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