The average kinetic energy of translation of oxygen molecules in the gas is 5.05 × 10⁻²¹
The given data is
n = 2
v = 20
P = 92
K.E = 3 / 2 KbT
= 3 / 2 PV / N
= 3 / 2 Pv / nNa
K.E = 3 / 2 × 9 × 1.013 × 10⁵ × 20 × 10⁻³ / 2 × 6.022 × 10²³
K. E = 5.05 × 10⁻²¹ J
<h3>Average kinetic energy</h3>
The average kinetic energy (K) is equal to one half of the mass of each gas molecule times the RMS speed squared
Hence, the average kinetic energy is 5.05 × 10⁻²¹ J
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Answer:
Explanation:
The<em> heat</em> to <em>vaporize</em> a l<em>iquid</em> is equal to the amount of liquid in moles multiplied by the specific <em>heat of vaporiztion</em> per mole.
First, calculate the number of moles in 35.5g of <em>butane</em>.
- Molar mass of butane: 58.124 g/mol
- Number of moles = mass in grams/molar mass
- Number of moles = 35.5g / 58.124g/mol = 0.6107632mol
Now, calculate the heat to vaporize that amount of <em>liquid butane</em>:
- Heat = number of moles × specific heat of vaporization
- Heat = 0.6107632mol × 21.3kJ/mol = 13.0 kJ
The answer must be reported with 3 significant figures.
Answer:
72.6% Error
Explanation:
% error = 
58.44 is the weight of NaCl
<u>Answer:</u> The additional information that is helpful in calculating the mole percent of XCl(s) and ZCl(s) is the molar masses of Z and X
<u>Explanation:</u>
To calculate the mole percent of a substance, we use the equation:
Mass percent means that the mass of a substance is present in 100 grams of mixture
To calculate the number of moles, we use the equation:
We require the molar masses of Z and X to calculate the mole percent of Z and X respectively
Hence, the additional information that is helpful in calculating the mole percent of XCl(s) and ZCl(s) is the molar masses of Z and X
